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fenix001 [56]
4 years ago
6

.........................................

Chemistry
2 answers:
Dafna11 [192]4 years ago
8 0

Answer:

.................................................

Explanation:

brilliants [131]4 years ago
7 0

Answer: free points

Explanation:

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You are given a solid that is a mixture of na2so4 and k2so4.
Murljashka [212]

Here we have to calculate the amount of SO_{4}^{2-} ion present in the sample.

In the sample solution 0.122g of SO_{4}^{2-} ion is present.

The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-

K₂SO₄ = 2K⁺ +  SO_{4}^{2-}

(Na)₂SO₄=2Na⁺ +  SO_{4}^{2-}

Thus, BaCl₂+  SO_{4}^{2-} = BaSO₄↓ + 2Cl⁻ .

(Na)₂SO₄ and  K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of  SO_{4}^{2-} ion is precipitated in this reaction.  

The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.

Now the molecular weight of BaSO₄ is 233.3 g/mol.

We know the molecular weight of sulfate ion (SO_{4}^{2-}) is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of SO_{4}^{2-} ion is present.

Or. we may write in 233.3 g of BaSO₄ 96.06 g of SO_{4}^{2-} ion is present. So in 1 g of BaSO₄ \frac{96.06}{233.3}=0.411 g of SO_{4}^{2-} ion is present.

Or, in 0.298 g of the filtered mass (0.298×0.411)=0.122g of SO_{4}^{2-} ion is present.        

5 0
3 years ago
If 0.089 grams of KI is dissolved in 500g of H2O, what is the concentration of the resulting solution in parts per million?
frez [133]

Answer:

The concentration of the resulting solution in parts per million is 177.97

Explanation:

Parts per million (ppm), is a unit of measure for concentration that refers to the number of units of the substance per million units of the set.

The concentration in parts per million expressed in mass / mass is calculated by dividing the mass of the solute (ms) by the mass of the solution (md, sum of the mass of the solute and the mass of the solvent), both expressed in the same unit and multiplied by 10⁶ (1 million).

ppm=\frac{ms}{md} *10^{6}

So, being:

  • ms: 0.089 grams of KI
  • md: 0.089 grams of KI + 500 grams of H₂O= 500.089 grams

Replacing:

ppm=\frac{0.089 grams}{500.089 grams}*10^{6}

ppm= 177.97

<u><em>The concentration of the resulting solution in parts per million is 177.97</em></u>

6 0
3 years ago
Calculate the number of moles in 7.4g ca(oh)2
SCORPION-xisa [38]
First find the RFM (Relative Formula Mass) using a periodic table 
the RFM of Ca(OH)2 is = 74

then use the equation Moles = Mass / RFM

Moles = 7.4 / 74 = 0.1mol

<span>hope that helps</span>
6 0
4 years ago
How many moles are there in 2.35 x 10^24 molecules of h2o
svetoff [14.1K]

Answer:

Explanation:

Mole = no. Molecules/6.02×10^23

Mole = (2.35×10^24)/(6.02×10^23)

Mole = 3.9mole

6 0
4 years ago
What is the rule when "ao" or "oo" are together when naming covalent bonds
Gnoma [55]

They are converted into a single “o” when "ao" or "oo" are together when naming covalent bonds.

<h3>What is a covalent bond?</h3>

A covalent bond consists of the mutual sharing of one or more pairs of electrons between two atoms.

Sometimes, while naming the chemical compounds, a problem arises when compounds with “ao” and “oo” are written with -ide name. Conventionally, they are converted into a single “o”.

For example, the “ao” in the dichlorine hept-ao-xide (Cl_2O_7). This “ao” in the Cl_2O_7 can be converted into “o”. As the result, the correct name of this compound would be dichlorine hept-o-xide.

Hence, they are converted into a single “o” when "ao" or "oo" are together when naming covalent bonds.

Learn more about the covalent bond here:

brainly.com/question/12661797

#SPJ1

8 0
2 years ago
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