Here we have to calculate the amount of 
ion present in the sample.
In the sample solution 0.122g of ion is present.
The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-
K₂SO₄ = 2K⁺ +
(Na)₂SO₄=2Na⁺ +
Thus, BaCl₂+ = BaSO₄↓ + 2Cl⁻ .
(Na)₂SO₄ and K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of ion is precipitated in this reaction.
The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.
Now the molecular weight of BaSO₄ is 233.3 g/mol.
We know the molecular weight of sulfate ion () is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of ion is present.
Or. we may write in 233.3 g of BaSO₄ 96.06 g of ion is present. So in 1 g of BaSO₄ 
g of ion is present.
Or, in 0.298 g of the filtered mass (0.298×0.411)=0.122g of ion is present.
Answer:
The concentration of the resulting solution in parts per million is 177.97
Explanation:
Parts per million (ppm), is a unit of measure for concentration that refers to the number of units of the substance per million units of the set.
The concentration in parts per million expressed in mass / mass is calculated by dividing the mass of the solute (ms) by the mass of the solution (md, sum of the mass of the solute and the mass of the solvent), both expressed in the same unit and multiplied by 10⁶ (1 million).
So, being:
- md: 0.089 grams of KI + 500 grams of H₂O= 500.089 grams
Replacing:
ppm= 177.97
<u><em>The concentration of the resulting solution in parts per million is 177.97</em></u>
First find the RFM (Relative Formula Mass) using a periodic table
the RFM of Ca(OH)2 is = 74
then use the equation Moles = Mass / RFM
Moles = 7.4 / 74 = 0.1mol
<span>hope that helps</span>
Answer:
Explanation:
Mole = no. Molecules/6.02×10^23
Mole = (2.35×10^24)/(6.02×10^23)
Mole = 3.9mole
They are converted into a single “o” when "ao" or "oo" are together when naming covalent bonds.
<h3>What is a covalent bond?</h3>
A covalent bond consists of the mutual sharing of one or more pairs of electrons between two atoms.
Sometimes, while naming the chemical compounds, a problem arises when compounds with “ao” and “oo” are written with -ide name. Conventionally, they are converted into a single “o”.
For example, the “ao” in the dichlorine hept-ao-xide (
). This “ao” in the can be converted into “o”. As the result, the correct name of this compound would be dichlorine hept-o-xide.
Hence, they are converted into a single “o” when "ao" or "oo" are together when naming covalent bonds.
Learn more about the covalent bond here:
brainly.com/question/12661797
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