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Valentin [98]
3 years ago
9

25. Find the area of the trapezoid. Leave your answer in simplest radical form. The figure is not drawn to scale.

Mathematics
1 answer:
n200080 [17]3 years ago
6 0

Answer:

Option D. 44\ cm^{2}

Step-by-step explanation:

we know that

The area of a trapezoid is equal to

A=\frac{1}{2}[b1+b2]h

we have

b1=8\ cm

b2=(4+8+2)=14\ cm

h=4\ cm

substitute the values

A=\frac{1}{2}[8+14](4)=44\ cm^{2}

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Shane is following an English recipe for scones. The recipe calls for 1.2 kilograms of flour. How many pounds of flour, to the n
makkiz [27]

Answer:

3

Step-by-step explanation:

sorry i cant answer it wont let me

6 0
2 years ago
54 is 90% of what number?
Zarrin [17]

The answer is 60 surprisingly

7 0
3 years ago
I'm lost I need help
dangina [55]
So set both equations equal to each other then solve out of x and plug it back into the x equation to find the angles so start with x+5=2x+10 then subtract x from 2x and you will have 1x then subtract 10 from 5 leaving you with negative 5 then x equals negative 5 and then plug it back into the equation so for example 2 times negative 5 equals negative 10 plus positive 10 equals 0 so therefore x equals 0
3 0
3 years ago
Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.
Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

  • x-intercepts:

               (3-\sqrt{5},0) \\\\(3+\sqrt{5},0)

  • y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

    y=-x^2+6x-4

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

                 y=ax^2+bx+c

Where:    

                 a=-1;b=6;c=-4

The axis of symmetry is the vertical line with equation:

               x=-b/2a

Substitute  a=-1,\text{ and }b=6

          x=-6/[(2)(-1)]=-6/(-2)=3

Thus, the axis of symmetry is:

            x=3

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

               y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

        y=-x^2+6x-4=0

Use the quadratic equation:

       x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

         y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4

7 0
3 years ago
Answer this as soon as possible
kenny6666 [7]

Answer:

21+3t

If really want equation answer it would be -7 but it simplifying. :)

Step-by-step explanation:

6(4+t)-3(t+1)

Simplify parenthesis first.

24+6t-3t-3

Simplify like terms

24-3+6t-3t

21+3t

5 0
3 years ago
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