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pantera1 [17]
3 years ago
12

mb- The graph shows the relationship between time and the number of soda bottles a machine can make. Use the points (2,100) and

(4,200) to find the number of soda bottles the machine can make each minute ​
Mathematics
1 answer:
Evgesh-ka [11]3 years ago
5 0

Answer:

1200

Step-by-step explanation:

We can gather from what's given that y=20xy represents the total number of bottles produced in the given time in seconds, which is x. When x=1, y=20, This means that each second the machine can make 20 soda bottles. Each minute is 60 seconds, so when x=60, y=20*60 =1200 soda bottles.

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In a first -aid kit the ratio of large bandages is 3 to 2. Based on this ratio, how many large bandages are in the kit if there
11Alexandr11 [23.1K]

Answer:

  48

Step-by-step explanation:

The total number of ratio units is 3+2 = 5, and the 3 ratio units representing large bandages make up 3/5 of that total. Thus, large bandages will make up 3/5 of the total number of bandages:

  3/5×80 = 48 . . . . number of large bandages in the kit

7 0
4 years ago
I need an answer...............................
navik [9.2K]

Answer:

8 i think

Step-by-step explanation:

4 0
3 years ago
A cylindrical plastic pipe’s length is 12 cm and it’s radius is 2.5 cm. To the nearest tenth, what is the volume of the pipe?
NemiM [27]

Answer:

V = 235.6 cm³

Step-by-step explanation:

the formula for the volume of a cylinder of radius r and length h is

V = πr²h.  

Here, r = 2.5 cm and h = 12 cm, so the volume is:

V = π(2.5 cm)²(12 cm) = 75π cm³

To the nearest tenth, this volume would be V = 235.6 cm³

7 0
4 years ago
Read 2 more answers
20 POINTS!!!!
Lostsunrise [7]
15/4 - 6/5 , 300/20 -24/20, 276/20, 69/5
6 0
4 years ago
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p varies jointly as q and the square of r, and p = 200 when q = 2 and r = 3. Find p when q = 5 and r= 2.
Margarita [4]

Step-by-step explanation:

If a variables varies jointly, we can just divide it by the other variables in relation to it.

For example, since p variables jointly as q and square of r, then

\frac{p}{q {r}^{2} }  = k

where k is a constant

First, let find k. Substitute p= 200

q= 2, and r=3.

\frac{200}{2(3) {}^{2} }  = k

\frac{200}{18}  = k

\frac{100}{9}  = k

Now, since we know our constant, let find p.

\frac{p}{q {r}^{2} }  =  \frac{100}{9}

Q is 5, and r is 2.

\frac{p}{5( {2}^{2}) }  =  \frac{100}{9}

\frac{p}{20}  =  \frac{100}{9}

p =  \frac{2000}{9}

3 0
2 years ago
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