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2 years ago

Find the volume of triangular prism. NO LINKS

Mathematics

1 answer:

Brums [2.3K]2 years ago

7 0

Answer:

504

Step-by-step explanation:

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How many time does 16 go into 4

Artemon [7]

4 can go into 16 4 times

6 0

2 years ago

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Which point gives the vertex of ƒ(x) = –x2 + 4x – 3?

Dmitriy789 [7]

Answer:

The vertex is (2,1)

Step-by-step explanation:

ƒ(x) = –x^2 + 4x – 3

Factor out the negative

= -(x^2 -4x+3)

Factor

What 2 numbers multiply to +3 and add to -4

-3*-1 = 3

-3+-1 = -4

f(x) = -( x-3)(x-1)

Find the zeros

0 = -( x-3)(x-1)

0 = x-3 0 = x-1

x=3 x=1

The x value of the vertex is 1/2 way between the two zeros

(3+1)/2 = 4/2 =2

To find the y value, substitute x=2 in

f(2) = -( 2-3)(2-1)

=-(-1)(1) = 1

The vertex is (2,1)

4 0

2 years ago

If a vertical line is dropped from the x-axis to the point (12, –9) in the diagram below, what is the value of sec?

dem82 [27]

Answer:

Value of $\sec \theta = \frac{5}{4}$

Step-by-step explanation:

Given: A vertical line is dropped from the x-axis to the point (12, -9) as shown in the diagram below;

To find the value of $\sec \theta$ .

By definition of secants;

$\sec \theta = \frac{1}{\cos \theta}$

Now, first find the cosine of angle $\theta$

As the point (12 , -9) lies in the IV quadrant , where $\cos \theta > 0$

Consider a right angle triangle;

here, Adjacent side = 12 units and Opposite side = -9 units

Using Pythagoras theorem;

$(Hypotenuse side)^2= (12)^2 + (-9)^2 = 144 + 81 = 225$

$Hypotenuse = \sqrt{225} =15 units$

Cosine ratio is defined as in a right angle triangle, the ratio of adjacent side to hypotenuse side.

$\cos \theta = \frac{Adjacent side}{Hypotenuse side}$

then;

$\cos \theta = \frac{12}{15} = \frac{4}{5}$

and

$\sec \theta = \frac{1}{\cos \theta}= \frac{1}{\frac{4}{5}} = \frac{5}{4}$

therefore, the value of $\sec \theta$ is, $\frac{5}{4}$

5 0

2 years ago

Read 2 more answers

HELP A FELLA OUT Please

Vanyuwa [196]

I'll write "x" instead theta.

sin x + 1 = cos(2x)

formula: cos(2x) = 1 - 2sin²x

sin x + 1 = 1 - 2sin²x

2sin²x + sin x = 0

sin x (2sin x + 1) = 0

sin x = 0 or sin x = -1/2

x1 = πk and x2 = -π/6 + 2πk and

x3 = 5π/6 + 2πk

for domain 0≤x<2π :

x1 = 0 (for k=0 in x1)

x2 = π (for k=1 in x1

x3 = 11π/6 (for k=1 in x2)

x4 = 5π/6 (for k=0 in x3).

k is an integral.

8 0

2 years ago

Determine the graph of the polar equation r=4/(1-1/2cosx(theta))

crimeas [40]

Answer:

see below

Step-by-step explanation:

We assume you want the graph of ...

$r=\dfrac{4}{1-\frac{1}{2}\cos{(\theta)}}$

A graphing calculator or spreadsheet is useful for this.

You know cos(θ) = cos(-θ), so the graph is symmetrical about the x-axis. You can evaluate the function at a few points to find the general outline.

r at 0° = 8

r at 30° ≈ 7.05

r at 45° ≈ 6.19

r at 60° ≈ 5.33

r at 90° = 4

r at 120° = 3.2

r at 135° ≈ 2.96

r at 150° ≈ 2.79

r at 180° ≈ 2.67

6 0

3 years ago