Question

PHYSICS!! 30 PTS...

Answer 1

Answer: $3.52(10)^{-10} N$

Explanation:

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:  

$F=G\frac{m_{1}m_{2}}{r^2}$

Where:  

$F$ is the module of the force exerted between both bodies  

$G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$ is the universal gravitation constant.  

$m_{1}=0.006 kg$ and $m_{2}=55 kg$ are the masses of the pencil and the teenager, respectively.

$r=0.25 m$ is the distance between both bodies

Solving for $F$:

$F=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(0.006 kg)(55 kg)}{(0.25 m)^2}$

$F=3.52(10)^{-10} N$ This is the force of gravitational attraction between the pencil and the teenager, which is very small in this case