Please help me with this problem
1 answer:
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The area of the largest triangle would be 6 inches².
How did I get this? I'll explain first:
We would want our triangle to have the longest sides, so it can be big. If you think of a rectangle, a triangle can fit into it if:
The base (bottom) of the triangle is the same length as one side of the rectangle, and the other side of the triangle is perpendicular (90°) to the bottom and is the same length of the other side of the rectangle.
Okay, just picture it: two sides of the triangle are resting in the two sides of the rectangle, and the third side of the triangle is a line that splits the rectangle in half from one corner to the other.
I've added an image to explain.
The formula to find the area of a triangle is half of the base × height.
A of Δ = half of 3 × 4
A = 1.5 × 4 = 6 inches²!
How did I get this? I'll explain first:
We would want our triangle to have the longest sides, so it can be big. If you think of a rectangle, a triangle can fit into it if:
The base (bottom) of the triangle is the same length as one side of the rectangle, and the other side of the triangle is perpendicular (90°) to the bottom and is the same length of the other side of the rectangle.
Okay, just picture it: two sides of the triangle are resting in the two sides of the rectangle, and the third side of the triangle is a line that splits the rectangle in half from one corner to the other.
I've added an image to explain.
The formula to find the area of a triangle is half of the base × height.
A of Δ = half of 3 × 4
A = 1.5 × 4 = 6 inches²!