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Tems11 [23]
3 years ago
11

De que material estan echos los marcapasos​

Chemistry
2 answers:
Dahasolnce [82]3 years ago
4 0

Answer:

Titanio y litio.

Explanation:

El titanio y el litio son los materiales que componen los marcapasos.

ZanzabumX [31]3 years ago
3 0

Answer:

Hm creo que es La carcasa es de titanio y la batería está compuesta de acumuladores de litio y yodo, que pueden durar cerca de diez años. Los electrodos que lo componen pueden ser de distintos tipos, pero sus puntas, que no están aisladas, son de platino, y el número de los mismos dependerá de las necesidades de cada paciente

Explanation:

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Without what do carbohydrates fats and proteins can not be changed into energy
stepan [7]

vitamins is the answer to your question

5 0
4 years ago
To what volume would you need to dilute 200 mL of a 5.85M solution of Ca(OH)2 to make it a 1.95M solution?
Blizzard [7]

Answer: 600 mL

Explanation:

Given that;

M₁ = 5.85 m

M₂ = 1.95 m

V₁ = 200 mL

V₂ = ?

Now from the dilution law;

M₁V₁ = M₂V₂

so we substitute

5.85 × 200 = 1.95 × V₂

1170 = 1.95V₂

V₂ = 1170 / 1.95

V₂ = 600 mL

Therefore final volume is 600 mL

8 0
3 years ago
A 1.59 mol sample of Kr has a volume of 641 mL. How many moles of Kr are in a 4.41 L sample at the same temperature and pressure
Marina86 [1]

Answer:

The correct answer is 10.939 mol ≅ 10.94 mol

Explanation:

According to Avogadro's gases law, the number of moles of an ideal gas (n) at constant pressure and temperature, is directly proportional to the volume (V).

For the initial gas (1), we have:

n₁= 1.59 mol

V₁= 641 mL= 0.641 L

For the final gas (2), we have:

V₂: 4.41 L

The relation between 1 and 2 is given by:

n₁/V₁ = n₂/V₂

We calculate n₂ as follows:

n₂= (n₁/V₁) x V₂ = (1.59 mol/0.641 L) x 4.41 L = 10.939 mol ≅ 10.94 mol

5 0
3 years ago
In the EXPLORE section of your lesson 4.08 on Potential energy there were several animations to watch that provided a graphic il
Lunna [17]

Answer:

This is because no energy is being created or destroyed in this system

Explanation:

I think this is correct? I hope it helps.        

7 0
3 years ago
Read 2 more answers
How many milliliters of 2.19 M H2SO4 are required to react with 4.75 g of solid containing 21.6 wt% Ba(NO3)2 if the reaction is
Setler [38]

Answer:

1.7927 mL

Explanation:

The mass of solid taken = 4.75 g

This solid contains 21.6 wt% Ba(NO_3)_2, thus,

Mass of Ba(NO_3)_2 = \frac {21.6}{100}\times 4.75\ g = 1.026 g

Molar mass of Ba(NO_3)_2 = 261.337 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.026\ g}{261.337\ g/mol}

Moles= 0.003926\ mol

Considering the reaction as:

Ba(NO_3)_2+H_2SO_4\rightarrow BaSO_4+2HNO_3

1 moles of Ba(NO_3)_2 react with 1 mole of H_2SO_4

Thus,

0.003926 mole of Ba(NO_3)_2 react with 0.003926 mole of H_2SO_4

Moles of H_2SO_4 = 0.003926 mole

Also, considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity = 2.19 M

So,

2.19=\frac{0.003926}{Volume\ of\ the\ solution(L)}

Volume = 0.0017927 L

Also, 1 L = 1000 mL

<u>So, volume = 1.7927 mL</u>

5 0
3 years ago
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