Power is a measure of the rate of energy or work done on a system. It has units of energy per time. In SI, Joules per second and is equal to the units of Watts. So, for an 800 Watts hair straightener, the energy transfer per second would be 800 Joules.
Answer:
V₂ = 4.0L
Explanation:
Decreasing temperature => Decreasing Volume (Charles Law)
For a given volume, use a temperature ratio that will give a smaller volume.
Volume at lower temp = 4.6L(70K/82K) = 4.0L ... Using (82K/70K) would give a larger volume => contrary to temperature effects on gas volumes when pressure and mass are kept constant.
Pressure effects on Gas Volumes:
Note: The same idea is applied to pressure effects on gas volumes also except that changes in pressure affect gas volumes indirectly. That is, an increase in pressure => decrease in volume, or a decrease in pressure => increase in volume. Boyles Law => V ∝ 1/P.
Given a gas volume of 4.60L at 760mmHg, what is volume at 848mmHg?
Increasing pressure => Decreases Volume (Boyles Law)
For the given volume use a pressure ratio that will give a smaller volume.
Volume at higher pressure = 4.6L(760mm/848mm) =4.1L. Using (848mm/760mm) would give a larger volume => contrary to pressure effects on gas volume when temperature and mass of gas are kept constant.
In 250 mL of volumetric flask add 0.975875 grams of
and dissolve it in the 250 mL of water.
Given:
The solid of calcium fluoride.
To prepare:
The 250 mL solution of 0.100 M of fluoride ions from solid calcium fluoride.
Method:
Molarity of the fluoride ion solution needed = M = 0.100 M
The volume of the fluoride ion solution needed = V = 250 mL

The moles of fluoride ion needed = n
According to the definition of molarity:

Moles of fluoride ion = 0.025 mol
We know that solid calcium fluoride dissolves in water to give calcium ions and fluoride ions.

According to reaction, 2 moles of fluoride ions are obtained from 1 mole of calcium fluoride, then 0.025 moles of fluoride ions will be obtained from:

Moles of calcium fluoride = 0.0125 mol
Mass of calcium fluoride needed to prepare the solution :

Preparation:
- Weight 0.975875 grams of calcium fluoride
- Add weighed calcium fluoride to a volumetric flask of the labeled volume of 250 mL.
- Now add a small amount of water to dissolve the calcium fluoride completely.
- After this add more water up to the mark of the volumetric flask of volume 250 mL.
Learn more about molarity of solution ere:
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