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Ira Lisetskai [31]
3 years ago
12

A test has 20 question and is worth 100 points. The test consists of true or false questions worth 3 points each and multiple ch

oice questions worth 11 points each. How many multiple choice questions are on the test?
Mathematics
2 answers:
Blizzard [7]3 years ago
8 0
10 or 15 that is what I think
SVETLANKA909090 [29]3 years ago
3 0
X=number of true or false
y=number of multiplule choice

total questions is 20
x+y=20

total poits is 100
3x+11y=100

eliminate x's

multiply first equaiton by -3 and add to 2nd

-3x-3y=-60
<u>3x+11y=100 +</u>
0x+8y=40

8y=40
divide both sides by 8
y=5

5 multipule choice questions
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A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
How do you solve the photo below
VikaD [51]

Answer:

6

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Consumer products are required by law to contain at least as much as the amount printed on the package. For example, a bag of po
Troyanec [42]

Answer:

The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

Step-by-step explanation:

We are given that

Standard deviation, \sigma=0.2ounces

We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

P(x\geq 10)=0.99

Assume the bag weight distribution is bell-shaped

Therefore,

P(\frac{x-\mu}{\sigma}\geq 10)=0.99

We know that

z=\frac{x-\mu}{\sigma}

Using the value of z

Now,

\frac{10-\mu}{0.2}=0.99

10-\mu=0.99\times 0.2

\mu=10-0.99\times 0.2

\mu=9.802

Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

5 0
3 years ago
Select the values that make the inequality y≥2y≥2 true.
ExtremeBDS [4]

9514 1404 393

Answer:

  {2, 2.001, 2.01, 2.1, 3, 5, 7, 10}

Step-by-step explanation:

The symbol ≥ means "greater than or equal to", so any values 2 or greater will make the inequality true. From your list, those are ...

  2 2.001 2.01 2.1 3 5 7 10

3 0
2 years ago
I will give Brainliest!!!
mixer [17]

Answer: C

Step-by-step explanation:

x = 2\sqrt{y+2} - 6

x + 6 = 2\sqrt{y+2}

((x+6)/2 = \sqrt{y+2} )^2

(x+6/2)^2 = y+2

y = (x+6/2)^2 -2

y= 1/4x^2 +3x +7

3 0
3 years ago
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