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Ira Lisetskai [31]
3 years ago
12

A test has 20 question and is worth 100 points. The test consists of true or false questions worth 3 points each and multiple ch

oice questions worth 11 points each. How many multiple choice questions are on the test?
Mathematics
2 answers:
Blizzard [7]3 years ago
8 0
10 or 15 that is what I think
SVETLANKA909090 [29]3 years ago
3 0
X=number of true or false
y=number of multiplule choice

total questions is 20
x+y=20

total poits is 100
3x+11y=100

eliminate x's

multiply first equaiton by -3 and add to 2nd

-3x-3y=-60
<u>3x+11y=100 +</u>
0x+8y=40

8y=40
divide both sides by 8
y=5

5 multipule choice questions
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8.4 x 5.2 show your work
LuckyWell [14K]

Answer:

43.68

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Solve the following x/5=10<br>​
sergey [27]

Answer:

x = 50

Step-by-step explanation:

x/5 = 10

Multiply both sides of the equation by 5.

5(x/5) = 5(10)

x = 5(10)

x = 50

The value of x is 50.

6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%28%20%5Csin%5E%7B2%7D%20%28%20%5Cfrac%7B%5Cpi%7D%7B%204%20%7D%20%20-%20%20%5Calpha%20%29%20%2
guapka [62]

Step-by-step explanation:

\sin^2 (\frac{\pi}{4} - \alpha) = \frac{1}{2}(1 - \sin 2\alpha)

Use the identity

\sin^2 \theta = \dfrac{1 - \cos 2\theta}{2}

on the left side.

\dfrac{1 - \cos [2(\frac{\pi}{4} - \alpha)]}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\dfrac{1 - \cos (\frac{\pi}{2} - 2\alpha)}{2} = \frac{1}{2}(1 - \sin 2\alpha)

Now use the identity

\sin \theta = \cos(\frac{\pi}{2} - \theta)

on the left side.

\dfrac{1 - \sin 2\alpha}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\frac{1}{2}(1 - \sin 2\alpha) = \frac{1}{2}(1 - \sin 2\alpha)

4 0
2 years ago
Which points are collinear with A and N?
stepan [7]

Collinear points lie on the same line. So, you must look for other points that lie on the line that connects A and N. If you start from A and continue along that line, you can see that, after N, you will meet points M and F.

So, those points are collinear with A and N.

4 0
3 years ago
I NEED HELP
Dmitrij [34]

Answer:

-82, -83, -84

Step-by-step explanation:

Using a variable and corresponding expressions, we can set the sum of the consecutive integers equal to -249 and solve:

first integer: x

second integer: x + 1

third integer: x + 2

x + x + 1 + x + 2 = -249

Combine like terms: 3x + 3 = -249

Subtract 3 from both sides: 3x + 3 - 3 = -249 - 3  or 3x = -252

Divide both sides by 3: 3x/3 = -252/3

Solve for x: x = -84

first integer: -84

second integer: -84 + 1 = -83

third integer: -84 + 2 = -82

8 0
3 years ago
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