No, because something extra is being added/divided and there are too many variables on one side
To make this a little clearer, let's give the pairs of inequalities the same denominator:
<span>Question 1:
</span>

?

First, apply the common denominator to the first fraction:

Do the same for the second:

Nest, compare the two fractions:

Therefore:

>

<span>
Question Two:</span>

?

Apply the common denominator to fraction one:

Fraction two:

Evaluate:

>

Therefore:
<span>
> 
</span>
Hope this helps!
HEY THERE.
THE CORRECT ANSWER IS 36/63 = 4/7
Hope this helps you
If you're using the app, try seeing this answer through your browser: brainly.com/question/2762144_______________
Let


because that is the range of the inverse cosine funcition.
Also,
![\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\ \mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}](https://tex.z-dn.net/?f=%5Cmathsf%7Bcos%5C%2C%5Ctheta%3Dcos%5C%21%5Cleft%5Bcos%5E%7B-1%7D%5C%21%5Cleft%28%5Cdfrac%7B4%7D%7B5%7D%5Cright%29%5Cright%5D%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7Bcos%5C%2C%5Ctheta%3D%5Cdfrac%7B4%7D%7B5%7D%7D%5C%5C%5C%5C%5C%5C%20%5Cmathsf%7B5%5C%2Ccos%5C%2C%5Ctheta%3D4%7D)
Square both sides and apply the fundamental trigonometric identity:



But

which means

lies either in the 1st or the 2nd quadrant. So

is a positive number:
![\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\ \therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}](https://tex.z-dn.net/?f=%5Cmathsf%7Bsin%5C%2C%5Ctheta%3D%5Cdfrac%7B3%7D%7B5%7D%7D%5C%5C%5C%5C%5C%5C%0A%5Ctherefore~~%5Cmathsf%7Bsin%5C%21%5Cleft%5Bcos%5E%7B-1%7D%5C%21%5Cleft%28%5Cdfrac%7B4%7D%7B5%7D%5Cright%29%5Cright%5D%3D%5Cdfrac%7B3%7D%7B5%7D%5Cqquad%5Cquad%5Ccheckmark%7D)
I hope this helps. =)
Tags: <em>inverse trigonometric function cosine sine cos sin trig trigonometry</em>
Answer:
113.9 ft³
Step-by-step explanation:
==>Given:
Base area of square pyramid (B) = 17 ft²
Height of pyramid (h) = 20.1 ft
==>Required:
Volume of the square pyramid (V)
==>Solution:
Using the formula ⅓*B*h, let's find the volume of the pyramid as follows by plugging in our values:
V = ⅓*17*20.1
V = 341.7/3
V= 113.9 ft³
Volume of the square pyramid = 113.9 ft³