ACB = AC + BC
ACB = 122 + 192 = 314
The answer is b. 314 degrees
The angle that is between the segments NM and PN is the angle that their segments form. If we take away the side PM (in our heads), we can see that the angle formed is angle N, or angle PNM.
Since the perimeter of the square is 16cm, each side is 4cm.
If we subtract the area of the two unshaded triangles from the area of the square we will know the area of the shaded portion...
The small inverted triangle on the left has a height of 4 and a base of 1. The are of the bottom triangle has a height of 2 and a base of 4...
So the area of the two triangles is 4*1/2+2*4/2=2+4=6
The area of the square is just 4*4=16 so:
The shaded area is 16-6=10cm^2
The proportion of the shaded area to the total area is then:
10cm^2:16cm^2
5:8
Since this line is parallel to y = 3x + 1 their slopes are equal. The slope is equal to 3. The line is also passing the point (-3,4).
This is the format of the line parallel to y = 3x + 1
y = 3x+ b
This line passes through point (-3, 4)
Replacing the values of y and x coming from the coordinates of (-3, 4)
4 = 3 * (-3) + b
Solving for the y-intercept b
4 = -9 + b
b = 4 + 9
b = 13
Knowing the slope as equal to 3 and the y-intercept as 13 the equation of the line is
y = 3x+13
Answer:
width = 16 cm
length = 19 cm
Step-by-step explanation:
Let the width be x cm.
Given that length is 3 cm more than width then
length = x+3 cm
area of rectangle = 304 square cm. -----1
area of rectangle is given by
area =length * width
substituting from equation 1 and length and width in terms of x we have
304 = x(x+3)
As length cannot be negative hence x = 16
Thus width = x = 16 cm
length = x+3 = 16+3 = 19 cm
