Question

In a standard gas grill propane tank, there is approximately 4,579 mL of propane (C3H8). At a temperature of 55˚C, the tank has a pressure of 1,798 kPa. The tank is cooled to 25˚C and the pressure reduced to 1,025 kPa. What will the new volume be?

Answer 1

Answer:

7300 mL

Explanation:

The question is a bit misleading, since tanks generally have a constant volume.  But anyway, using ideal gas law:

PV = nRT

If amount of gas (n) is constant, then:

PV / T = constant

P₁V₁ / T₁ = P₂V₂ / T₂

(1798 kPa) (4579 mL) / (55 + 273) K = (1025 kPa) V / (25 + 273) K

V = 7298 mL

Rounded to two significant figures, the volume is 7300 mL.