Answer:
Speed, v = 7.83 m/s
Explanation:
It is given that,
Length of the bridge, l = 5 m
The road on the far side is 2.0 m lower than the road on this side, x = 2 m
The horizontal distance covered by the car is 5 meters and the vertical distance covered by the car is 2 meters.
Initial speed of the car, u = 0
Let t is the time taken by the car . Using the second equation of motion as :
For vertical distance :


Let v is the velocity to jump the stream. It is given by :
Horizontal distance, d = 5 m

v = 7.83 m/s
So, the car should travel with a speed of 7.83 m/s. Hence, this is the required solution.
Answer:
d. f
Explanation:
Based on the principle of operation of transformer, when a.c voltage is applied at the terminal of the primary coil (input coil), an alternating magnetic flux is produced in the iron core which links the secondary coil (output coil).
Also, an alternating e.m.f of <em>the same frequency</em> as that of primary coil (input coil) <u>will be induced in the secondary coil (output coil) by mutual inductance.</u>
Thus, If the input frequency is "f" then the output frequency will be "f" (since the frequency will be the same).
The correct option is "D"
The wave will decrease in its frequency due to a disturbing force acting upon it.
Answer:

or 88.3m/s^2
Explanation:
Using suvat where we list everything that we are given
s=49m
u=0m/s
v=93m/s
a=?
t=we are not given this value, so we don't use
using a formula that doesn't involve time:

rearranging to find acceleration by subtracting u^2 on both sides

then dividing 2s on both sides


so the acceleration is 88.3ms^-2 (1dp)