Answer: c]bronchus (bronchi, pl.)
Explanation:
Answer:
A) 0.1 a, 0.9 A
Explanation:
According to the given information, all the individuals in the founder population had free earlobes. Since the allele for the free earlobes (A) is dominant over the one for the attached earlobes (a), the genotype of each of the homozygous dominant founder individual would be "AA". Humans are diploid and one individual has two alleles for each gene in its genome. Total number of alleles for the earlobe in the founder population = 10 x 2 = 20.
Frequency of dominant allele, A in the founder population = total number of homozygous dominant individuals x 2 + the total number of heterozygous genotype / total alleles for the earlobe in the population. There were 8 homozygous dominant and 2 heterozygous dominant individuals in the population.
So, frequency of dominant allele = 8 x 2 + 2 / 20 = 16 + 2 / 20 = 18/20 = 0.9
Since p+q=1; frequency of recessive allele "a" = 1-p = 1-0.9 = 0.1
Answer:
Cytokinesis is the stage of the cycle when the genetic information is replicated, resulting in two daughter cells and takes place after mitosis.
Explanation:
Prothallus represents a gametophyte in the life
cycle of fern.
<span>A prothallium, or </span>prothallus<span> (from Latin pro = forwards and Greek θαλλος
(thallos) = twig) is usually the gametophyte stage in the life of a fern or
other pteridophyte. Occasionally the term is also used to describe the young
gametophyte of a liverwort or peat moss as well.</span>
The correct answer between all
the choices given is the second choice or letter B. I am hoping that this
answer has satisfied your query and it will be able to help you in your
endeavor, and if you would like, feel free to ask another question.
