Answer:
In order to balance the chemical equation, you need to make sure the number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side. In order make both sides equal, you will need to multiply the number of atoms in each element until both sides are equal.
Molecules in a gas have lots of energy and spread out even more than molecules in a liquid. Warm water has more energy than cold water, which means that molecules in warm water move faster than molecules in cold water
In order to convert mm³ to m³, we use the conversion factor of 1m = 1000 mm. Also, the conversion factor of mm³ to cm³, we use the factor of 1cm = 10 mm.
= (0.45 mm³) x (1 m/ 1000 mm)³ = 4.5 x 10^-10 m³
= (0.45 mm³) x (1 cm/10 mm)³ = 4.5 x 10^-4 cm³
Thus, the answer is letter B.
The catabolism of glucose has an equation of C6H12O6 + 6O2 = 6CO2 +6 H20. Hence for every mole of glucose, 6 moles of CO2 is produced. Given 22 grams of CO2, that is 0.5 mol CO2, we multiply this by 1/6, we get the number of moles of glucose equal to 1/12 mol. The mass of glucose needed is obtained by multiplying this by molar mass of glucose which is 180 g/mol. This is equivalent 15 grams of glucose.
Lithium has charge of +1 and bromide has charge of - 1. So they combine to form the compound lithium bromide which is expressed as LiBr.
<h3><u>Explanation:</u></h3>
Lithium is an alkali metal placed in group 1 or periodic table. It has a valency of 1 which is achieved as lithium loses an electron to achieve a charge of +1.
Bromine is a halogen which is placed in group 17 of periodic table. It has a valency of 1 which is achieved as bromine looses an election to achieve a charge of - 1.
Lithium is the cation and bromide is the anion. So lithium is written in front and bromine following the cation. And as both of their valencies are 1, so they form the compound LiBr.
