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Liula [17]
3 years ago
5

Please answer this question for me I will answer your questions too I promise!!

Chemistry
2 answers:
Lyrx [107]3 years ago
7 0

Answer:

C

Explanation:

The airplanes speed would decrease

Savatey [412]3 years ago
6 0

Answer:

c

Explanation:

please help me on my most recent question

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A substance is tested and has a pH of 7.0. How would you classify it?
Alexandra [31]

Answer:

C

Explanation:

The substance would be classified as neutral, so C.

5 0
3 years ago
Read 2 more answers
Which of the following BEST describes a way in which water moves in the water cycle?
____ [38]

Answer: Its A or D                                                        

wish i had an actual answer sorry..  

6 0
3 years ago
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What are the two properties of Graphite that are different from the properties of Diamond?
Rus_ich [418]

Answer:

Graphite is insoluble in water and organic solvents - for the same reason that diamond is insoluble. Attractions between solvent molecules and carbon atoms will never be strong enough to overcome the strong covalent bonds in graphite. conducts electricity.

Explanation:

Brainlest please?

5 0
3 years ago
For the following reaction, KcKc = 255 at 1000 KK.
bonufazy [111]

Answer :

The equilibrium concentration of CO is, 0.016 M

The equilibrium concentration of Cl₂ is, 0.034 M

The equilibrium concentration of COCl₂ is, 0.139 M

Explanation :

The given chemical reaction is:

                           CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

Initial conc.      0.1550      0.173           0

At eqm.          (0.1550-x)  (0.173-x)         x

As we are given:

K_c=255

The expression for equilibrium constant is:

K_c=\frac{[COCl_2]}{[CO][Cl_2]}

Now put all the given values in this expression, we get:

255=\frac{(x)}{(0.1550-x)\times (0.173-x)}

x = 0.139 and x = 0.193

We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.139

The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M

The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M

The equilibrium concentration of COCl₂ = x = 0.139 M

5 0
3 years ago
Consider the reaction of magnesium metal with hydrochloric acid to produce magnesium chloride and hydrogen gas. If 3.29 mol of m
gregori [183]

Answer:

1.645 moles of excess reactant that is of magnesium metal are left over.

Explanation:

Moles of magnesium metal = 3.29 mol

Moles of HCl = 3.29 mol

Mg(s)+2HCl(aq)\rightarrow MgCl_2(aq)+H_2(g)

According to recation, 2 moles of HCl reacts with 1 mol of magnesium metal, then 3.29 moles of HCl will react with :

\frac{1}{2}\times 3.29 mol=1.645 mol of magnesium metal

Moles of HCl left = 3.29mol - 3.29 mol = 0

Moles of magnesium metal left = 3.29 mol - 1.645 mol = 1.645 mol

1.645 moles of excess reactant that is of magnesium metal are left over.

7 0
3 years ago
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