Answer:
1.33L of gas
Explanation:
1 mole of Baking soda (NaHCO₃) reacts with acetic acid producing 1 mole of CO₂, water and sodium acetate, thus:
NaHCO₃ + CH₃COOH → NaCH₃COO + H₂O + CO₂
5g of NaHCO₃ (Molar mass: 84g/mol) are:
5g × (1mol / 84g) = 0.0595 moles of NaHCO₃ that produce 0.0595 moles of CO₂ -Moles of gas-.
If 1 mole of gas occupies 22.4L, 0.0595 moles occupy:
0.0595 moles gas × (22.4L / mol) = <em>1.33L of gas</em>
True because it seems that is like a pattern it's always 6
Answer:
Which of the following
properties distinguishes a solution
oversaturated with a dilute?
- The supersaturated solution is one in which the solvent has dissolved more solute than it can dissolve in the saturation equilibrium. The solute can be a solid, or a gas. The molecules of the solvent surround those of the solute and seek to open space between themselves to be able to harbor more amount of solute.
- A dilute solution is a solution that has not reached the maximum concentration of solute dissolved in a solvent. The additional solute will dissolve when added in a dilute solution and will not appear in the aqueous phase.
It is considered a state of dynamic equilibrium where the speeds in which the solvent dissolves the solute are greater than the recrystallization rate.
Answer:
1
Explanation:
The empirical formula describes the simplest whole number ratio of each type of atom in a compound. To find this formula, you need to (1) convert grams of each element to moles (via their atomic masses) and then (2) find the ratio of each element (by dividing each molar value by the smallest mole value).
(Step 1)
Atomic Mass (Zn): 65.380 g/mol
Atomic Mass (C): 12.011 g/mol
Atomic Mass (O): 15.998 g/mol
10.40 grams Zn 1 mole
------------------------ x ------------------------ = 0.159 moles Zn
65.380 grams
1.92 grams C 1 mole
--------------------- x ----------------------- = 0.160 moles C
12.011 grams
7.68 grams O 1 mole
---------------------- x ------------------------ = 0.480 moles O
15.998 grams
(Step 2)
0.159 moles Zn / 0.159 = 1 atom Zn
0.160 moles C / 0.159 = 1 atom C
0.480 moles O / 0.159 = 3 atom O
The empirical formula is Zn₁C₁O₃. Therefore, the value that should be in the space is 1.
