Answer:
<h3>0.329m/s</h3>
Explanation:
According to law of conservation of momentum, the momentum of the object before collision is equal to that of the object after collision. Using the formula
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are the respective initial velocities
v is the final velocity
Given
m1 = 0.190kg
u1 = 1.5m/s
m2 = 0.305kg
u2 = -0.401m/s
Substitute
0.19(1.5)+(0.305)(-0.401) = (0.19+0.305)v
0.285 - 0.122305 = 0.495v
0.162695 = 0.495v
v = 0.162695 /0.495
v = 0.329m/s
<em>Hence their velocities after collision is 0.329m/s in the positive x direction</em>
<em></em>
Answer:
n = 4 x 10¹⁸ photons
Explanation:
First, we will calculate the energy of one photon in the radiation:
where,
E = Energy of one photon = ?
h = Plank's Constant = 6.625 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of radiation = 567 nm = 5.67 x 10⁻⁷ m
Therefore,
E = 3.505 x 10⁻¹⁹ J
Now, the number of photons to make up the total energy can be calculated as follows:
<u>n = 4 x 10¹⁸ photons</u>
Answer:
a. before
Explanation:
Did the displacement at this point reach its maximum of 2 mm before or after the interval of time when the displacement was a constant 1 mm?
from the graph given from a source. the vertical axis represents the displacement of the graph motion, whilst the horizontal side is representing the time variable of the motion .
displacement is distance in a specific direction.
before the displacement was maximum at 2mm was instant at time=0.04s.
But later was constant at 0.06s at a displacement point of 1mm
