The resistance of wire B will be D. 1/2R
<h3>What is resistance?</h3>
It should be noted that resistance simply means the measure of the opposition to the current flow that's in an electric circuit.
Based on the information given, the resistance will be calculated thus:
= 2L/4A
= 1/2pL/A
= R/2
Therefore, the resistance of wire B will be D. 1/2R
Learn more about resistance in:
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Two wires A and B with circular cross sections are made of the same metal and have equal lengths, but the resistance of wire A is three times greater than that of wire B. (ii) What is the ratio of the radius of A to that of B
(a) 4 R (b) 2 R (c) R (d) 1/2R (e) 1/4R
Answer:
current in water = 0.924 A
Explanation:
Let the current in each row be i.
Thus, current in water is contributed by each row and total current in water becomes 140i.
We are given;
emf of each electroplaque = 0.15 V
Number of electroplaques = 5000
internal resistance = 0.25 Ω
resistance = 800Ω
Applying Kirchoff's Voltage Law to row and water, we have;
5000E − (5000r)i − 800(140i) = 0
Rearranging;
5000E = (5000r)i + 800(140i)
Plugging in the relevant values;
5000 x 0.15 = i((5000 x 0.25) + 112,000)
750 = 113,250i
i = 750/113,250
i = 0.0066 A
Recall earlier, the current in water is 140i.
Thus, current in water = 140 x 0.0066
= 0.924
Answer:
Distance is path length covered by particle. When particle moves along half circle, it covers half the circumference therefore distance covered is (2×pi×r)/2 = pi× r. ... Hence displacement is equal to diameter or 2 times the radius of circle.
Wow ! This one could have some twists and turns in it.
Fasten your seat belt. It's going to be a boompy ride.
-- The buoyant force is precisely the missing <em>30N</em> .
-- In order to calculate the density of the frewium sample, we need to know
its mass and its volume. Then, density = mass/volume .
-- From the weight of the sample in air, we can closely calculate its mass.
Weight = (mass) x (gravity)
185N = (mass) x (9.81 m/s²)
Mass = (185N) / (9.81 m/s²) = <u>18.858 kilograms of frewium</u>
-- For its volume, we need to calculate the volume of the displaced water.
The buoyant force is equal to the weight of displaced water, and the
density of water is about 1 gram per cm³. So the volume of the
displaced water (in cm³) is the same as the number of grams in it.
The weight of the displaced water is 30N, and weight = (mass) (gravity).
30N = (mass of the displaced water) x (9.81 m/s²)
Mass = (30N) / (9.81 m/s²) = 3.058 kilograms
Volume of displaced water = <u>3,058 cm³</u>
Finally, density of the frewium sample = (mass)/(volume)
Density = (18,858 grams) / (3,058 cm³) = <em>6.167 gm/cm³</em> (rounded)
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I'm thinking that this must be the hard way to do it,
because I noticed that
(weight in air) / (buoyant force) = 185N / 30N = <u>6.1666...</u>
So apparently . . .
(density of a sample) / (density of water) =
(weight of the sample in air) / (buoyant force in water) .
I never knew that, but it's a good factoid to keep in my tool-box.
Answer:
If one cup falls down then there will be 59 cups left.
