The weight required to stretch the spring 12.5 cm is 7.5 N (Option A)
<h3>Data obtained from the question</h3>
- Initial weight (W₁) = 3 N
- Initial Length (L₁) = 5 cm
- New length (L₂) = 12.5 cm
- New Weight (W₂) =?
<h3>How to determine the new weight </h3>
The new weight required to stretch the spring can be obtained as follow:
W₁ / L₁ = W₂ / L₂
3 / 5 = W₂ / 12.5
Cross multiply
W₂ × 5 = 3 × 12.5
Divide both sides by 5
W₂ = (3 × 12.5) / 5
W₂ = 7.5 N
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Explanation:
if two individual forces are of equal magnitude and opposite direction, then the force is said to be balanced. when there is an individual force that is not being balanced by a force of equal magnitude and in the opposite direction.
Answer: 0.1125A
Explanation:
We need to know the total resistance which will be:
R = R1+R2
where,
R1 = 20 ohm
R2 = 60 ohm
Therefore, R = 20 + 60 = 80 ohm
We should note that from Ohm's law
v = iR
i = v/R
where,
i = 9/80 = 0.1125 A
Therefore, the current that flows out of the battery is 0.1125A
Answer:
b) 105220.8 m
c) 65.38 miles
d) Kenneth's home
Explanation:
Velocity of Sarah = 31 m/s east
Velocity of Kenneth = 65 mph = 65×(1609.34/3600) m/s west
Time in seconds = 29.2×60 = 1752 s
Displacement = Velocity × time
Displacement of Sarah = 31×1752 = 54312 m
Displacement of Kenneth = 65×(1609.34/3600)×1752 = 50908.8 m
b) So, distance between their homes in meters is 54312 m + 50908.8 m = 105220.8 m
c) Converting to miles
Their homes are 65.38 miles apart
d) They met closer to Kenneth's house (50908.8 m)
Always getting sleepy after lunch is part of data collection.