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Sonbull [250]
2 years ago
6

You are traveling at 16m/s for 18 seconds. What is your displacement?

Physics
1 answer:
nekit [7.7K]2 years ago
4 0

Answer:

Image result for You are traveling at 16m/s for 18 seconds. What is your displacement?

The average velocity of the object is multiplied by the time traveled to find the displacement. The equation x = ½( v + u)t can be manipulated, as shown below, to find any one of the four values if the other three are known.

Explanation:

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In projectile mtion, what is the y-component of the initial velocity? if V= Vi = 100 m/s and the angle with horizontal axis Θ =
Damm [24]

Answer:

hence the y - component of the velocity is 50m/s

4 0
3 years ago
A wave propagates at a well defined velocity that depends on the properties of the medium that carries the wave. True or false?
likoan [24]

Answer:

True

Explanation:

A wave is generated as a result of oscillations which creates disturbances in the medium and these disturbances termed as waves propagates or travels from one point to another.

Waves can be classifies as:

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A wave travels at a specific velocity depending on the type of the medium in which it propagates.

7 0
3 years ago
A light-year is the distance that light travels in one year. The speed of light is 3.00 × 108 m/s. How many miles are there in o
Alinara [238K]

Answer:

(a) 5.88\times 10^{12}mi

Explanation:

We have given speed of light c=3\times 10^8m/sec

Given time = 1 year =365 days

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1 hour = 60×60 = 3600 sec

In one day = 24 hour = 24×60×60=86400 sec

So in 365 days = 365×86400=3.1536\times 10^7sec

We know that distance = speed ×time=3.1536\times 10^7\times 3\times 10^8=9.46\times 10^{15}m

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8 0
3 years ago
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Answer:

U = √Rg/sin2θ

Explanation:

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According to the range formula,

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Cross multiplying we have;

Rg = U²sin2θ

Dividing both sides by sin2θ, we have;

U² = Rg/sin2θ

Taking the square root of both sides we have;

√U² = √Rg/sin2θ

U = √Rg/sin2θ

Therefore, his average speed if he is to meet the ball just before it hits the ground is √Rg/sin2θ

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Which of the following is a common downside of net pens, one of the most common forms of aquaculture?
Eduardwww [97]

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Answer is overcrowding aka answer choice A. I got the question and got it right. Please mark brainliest. Have a good day! :)

Explanation:

8 0
3 years ago
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