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3 years ago

You are traveling at 16m/s for 18 seconds. What is your displacement?

Physics

1 answer:

nekit [7.7K]3 years ago

4 0

Answer:

Image result for You are traveling at 16m/s for 18 seconds. What is your displacement?

The average velocity of the object is multiplied by the time traveled to find the displacement. The equation x = ½( v + u)t can be manipulated, as shown below, to find any one of the four values if the other three are known.

Explanation:

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The gage pressure in a liquid at a depth of 3 m is read to be 39 kPa. Determine the gage pressure in the same liquid at a depth

ioda

Answer: 117 kPa

Explanation:

For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa

For the liquid at depth 9m, the gauge pressure is equal to= P₂

Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.

So, For finding gauge pressure we have formula P= ρ * g * h

Also gravity also remains same for both liquids

So taking ratio of their respective pressures we have

$\frac{P_{1} }{\\P_2}$ = $\frac{density * g * h_1}{density * g * h_2}$

So $\frac{39}{P_2}$ = $\frac{3}{9}$

Or P₂= 39 * 3 = 117 kPa

5 0

3 years ago

How is the direction of a vector affected when it is multiplied by a scalar?

pantera1 [17]

The direction of a vector multiplied by a scalar is only affected if the scalar is negative, in which case the vector will now be in the opposite direction. If the scalar is positive, the vector will only change in magnitude

6 0

3 years ago

A block is released from rest, at a height h, and allowed to slide down an inclined plane. There is friction on the plane. At th

GREYUIT [131]

Here the block has two work done on it

1. Work done by gravity

2. Work done by friction force

So here it start from height "h" and then again raise to height hA after compressing the spring

So work done by the gravity is given as

$W_g = m_A g(h - h_A)$

Now work done by the friction force is to be calculated by finding total path length because friction force is a non conservative force and its work depends on total path

$W_f = -(\mu m_A g cos\theta)(\frac{h}{sin\theta} + \frac{h_A}{sin\theta})$

$W_f = -\mu m_A g cot\theta(h + h_A)$

Total work done on it

$W = m_A g(h - h_A) - \mu m_A g cot\theta(h + h_A)$

So answer will be

None of these

7 0

3 years ago

Read 2 more answers

Assume that the temperature, 40C, and volume of the gas, 6 liters, remain constant. At 2 atmosphere of pressure, there are 0.036

MAVERICK [17]

Answer:PV=nRT

Ideal gas equation

Explanation:

PV=nRT

Ideal gas equation

7 0

4 years ago

An object travels along a straight line across a horizontal surface, and its motion is described by the velocity versus time gra

Mkey [24]

Answer:

C.)Finding the area bound by the horizontal axis and the curve from 0 s to 5 s

D.)Using Average Speed = total distance/total and multiplying the average speed of 5m/s by a total time of 5 s

Explanation:

The graph seems to be missing, however we can still answer the question.

In fact, we have to keep in mind the following facts:

- In a velocity-time graph, the area under the curve represents the displacement of the object, while the slope of the curve corresponds to its acceleration.

From this, we can already say that the following option:

C.)Finding the area bound by the horizontal axis and the curve from 0 s to 5 s

is correct, while the statement

A.)Finding the slope of the line between 0 s to 5 s

is wrong.

Moreover, the average speed of an object in motion is given by

$v=\frac{d}{t}$

where d is the total distance covered while t is the total time taken. Once we have calculated the average speed, the total displacement over a certain time period can be simply calculated by multiplying the average speed by the time interval: so, the option

D.)Using Average Speed = total distance/total and multiplying the average speed of 5m/s by a total time of 5 s

is also correct.

The last option remained:

B.)Dividing the change in velocity between 0 s to 5 s by the change in time

is wrong, because in this way we are calculating the acceleration, not the displacement.

6 0

3 years ago