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3 years ago

2. If a tricycle has a kinetic energy of 360 J and a mass of 4 kg, what is its velocity?

Physics

1 answer:

BaLLatris [955]3 years ago

5 0

Answer:

13.42m/s

Explanation:

0.5 multiply by 4 = 2kg

360J divided by 2kg = 180

square root 180= 13.42m/s

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Which of the following objects is in dynamic equilibrium?

Vera_Pavlovna [14]

a. A car driving in a straight line at 20 m/s.

Explanation:

An object is in a state of equilibrium when no force is acting upon it. There are two types of equilibrium; static equilibrium and dynamic equilibrium.

Static equilibrium is a state when a body is at rest.

Dynamic equilibrium is an equilibrium state when a body is moving at a constant velocity. (Rectilinear Motion).

A car moving in a straight line at 20 m/s has a constant velocity and hence no force is acting on it. So, it is in dynamic equilibrium.

A book sitting on a table without moving is not is dynamic equilibrium but in static equilibrium.

A boy jumping off a diving board in not in equilibrium as gravitational force is acting upon him and he has a changing velocity.

A motorcycle going in a circle at a constant speed has changing velocity because the direction of the motion is constantly changing hence it is not in the state of motion.

Keywords: velocity, force, equilibrium, static equilibrium, dynamic equilibrium

Learn more about dynamic equilibrium from brainly.com/question/12880727

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3 years ago

Which subatomic particle was discovered by researchers working with cathode ray tubes

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The electron was discovered by researchers working with cathode ray tubes.

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What are three related words to centripetal force?

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4 years ago

A counterflow double-pipe heat exchanger is used to heat water from 20°C to 80°C at a rate of 1.2 kg/s. The heating is to be com

bixtya [17]

Answer:L=109.16 m

Explanation:

Given

initial temperature $=20^{\circ}C$

Final Temperature $=80^{\circ}C$

mass flow rate of cold fluid $\dot{m_c}=1.2 kg/s$

Initial Geothermal water temperature $T_h_i=160^{\circ}C$

Let final Temperature be T

mass flow rate of geothermal water $\dot{m_h}=2 kg/s$

diameter of inner wall $d_i=1.5 cm$

$U_{overall}=640 W/m^2K$

specific heat of water $c=4.18 kJ/kg-K$

balancing energy

Heat lost by hot fluid=heat gained by cold Fluid

$\dot{m_c}c(T_h_i-T_h_e)= \dot{m_h}c(80-20)$

$2\times (160-T)=1.2\times (80-20)$

$160-T=36$

$T=124^{\circ}C$

As heat exchanger is counter flow therefore

$\Delta T_1=160-80=80^{\circ}C$

$\Delta T_2=124-20=104^{\circ}C$

$LMTD=\frac{\Delta T_1-\Delta T_2}{\ln (\frac{\Delta T_1}{\Delta T_2})}$

$LMTD=\frac{80-104}{\ln \frac{80}{104}}$

$LMTD=91.49^{\circ}C$

heat lost or gain by Fluid is equal to heat transfer in the heat exchanger

$\dot{m_c}c(80-20)=U\cdot A\cdot$ (LMTD)

$A=\frac{1.2\times 4.184\times 1000\times 60}{640\times 91.49}=5.144 m^2$

$A=\pi DL=5.144$

$L=\frac{5.144}{\pi \times 0.015}$

$L=109.16 m$

6 0

3 years ago

A 720 kg roller-coaster starts off from Location A. Assuming friction does not impede the car's motion, what will be the change

vaieri [72.5K]

We know, Potential Energy = m * g * h
Here, mass & gravity would be same, but their height will change so it will be:

ΔU = U₂ - U₁
ΔU = mgh₂ - mgh₁
ΔU = mg (h₂ - h₁)

Hope this helps!

7 0

3 years ago

Read 2 more answers