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Complete Question
Write a rational equation that relates the desired percentage p, to the amount A of a 30% solution that needs to be added to 1 liter of 10% acid solution to make a blend that is p% acid, where 0<p<100 . What is a reasonable restriction on the set of possible values of ? Explain your answer.
Answer:
100(0.1 + 0.3A)= (1 + A) P
Step-by-step explanation:
A of a 30% solution that needs to be added to 1 liter of 10% acid solution to make a blend that is p% acid,
Hence,
10% of 1 + 30% of A = p%(1 + A)
0.10 + 0.3A = (p/100)(1 + A)
Divide both sides by 1 + A
0.1 + 0.3A/ 1 + A = p/100
Cross Multiply
100(0.1 + 0.3A) = 1 + A(p)
From the above calculation, we can see that, the blend that would be formed is not lower than 10% or greater than 30%
10% < p< 30%
Answer: no you can't you can only use 5 numbers when going by 4's
Step-by-step explanation: 4, 8, 12, 16, 20
Answer:
2.55
Step-by-step explanation:1
Convert 1121\frac{1}{2}121 to improper fraction. Use this rule: abc=ac+bca \frac{b}{c}=\frac{ac+b}{c}acb=cac+b.
34+3.3−1×2+12\frac{3}{4}+3.3-\frac{1\times 2+1}{2}43+3.3−21×2+1
2
Simplify 1×21\times 21×2 to 222.
34+3.3−2+12\frac{3}{4}+3.3-\frac{2+1}{2}43+3.3−22+1
3
Simplify 2+12+12+1 to 333.
34+3.3−32\frac{3}{4}+3.3-\frac{3}{2}43+3.3−23
4
Simplify.
5.12\frac{5.1}{2}25.1
5
Simplify.
2.552.552.55
It would be 32-4x=12
32-4(5)=12
32-20=12
12=12
Answer:
Speed of car B is 33 km/h and speed of car A is 
Step-by-step explanation:
Let speed of car B be 
km/h
Speed of car A is 12 km/h more than car B.
Therefore,
Speed of car A = 
km/h
Distance = Speed × Time
Distance travelled by car A in 4 hours = 
km = 
km
Distance travelled by car B in 4 hours = 
km
Also, cars A and B are 312km apart after 4 hours.
Speed of car B is 33 km/h and speed of car A is 
