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taurus [48]
3 years ago
13

Find the value of x. 4 14 3 6

Mathematics
2 answers:
nadezda [96]3 years ago
5 0

Hello from MrBillDoesMath!

Answer:

4

Discussion:

As vertical angles are equal,    Angle 3 = Angle 2,  so

Angle 3 = 3x + 2     (A)

Angles 3 and 7 are corresponding angles and hence equal. So

Angle 3 = Angle 7   =>  use (A) above and Angle 7 =  x + 10

3x + 2 = x + 10  =>   subtract x from both sides

3x -x + 2 = x - x + 10  =>

2x + 2 = 10                 => subtract 2 from both sides

2x = 10 -2 = 8

x = 8/2 = 4


which is the first choice



Thank you,

MrB

belka [17]3 years ago
4 0
The answer is A.) 4..
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Step-by-step explanation:

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City B = 21°42′ = 21° + \frac{42}{60} = 21.7° = 21.7° × \frac{\pi}{180} = 0.3785 rad

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distance between City A and City B

solution

we first get here central angle between A and B city is

central angle between A and B city = 0.6297 rad - 0.3785 rad

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distance = 3960 miles × (0.6297 rad - 0.3785 rad )

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puteri [66]

Answer:

Width: 7

Length: 14

Step-by-step explanation:

The area of a rectangle can be found my multiplying the length by the width. We do not know neither the length nor the width. However, we do know that the length is 7 feet longer than the width. Because we do not know the value of either side, let's let x represent the width.

Since the length is 7 feet longer, we can represent the length by x+7.

Now that we have our values for the length and the width we can multiply them together to find our area.

(x)(x+7)=x^{2} +7x

Now we have our equation, so we can address the changes made by the original question. The original question states that when 7 is added to both the length and width the area becomes 3 times larger. To do so simply increase each side by 7 by adding 7 to the original values.

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And multiply our area by 3.

3(x^{2} +7x)

set these equal to each other to find your new equation.

(x+7)(x+14)=3(x^{2} +7x)

Now you need to solve for x. To do this first muliply (x+7) and (x+14).

(x+7)(x+14)=\\x^{2} +14x+7x+98=\\x^{2} +21x+98

Then multiply 3(x^{2} +7x)

3(x^{2} +7x)=\\3x^{2} +21x

Now you can begin solving for x.

x^{2} +21x+98=3x^{2} +21x

Subtract x^{2} from both sides.

21x+98=2x^{2} +21x

Subtract 21x from both sides.

98=2x^{2}

Divide by 2.

49=x^{2}

And finally take the sqaure root of both sides.

\sqrt{x^{2} }=\sqrt{49}\\x=7

Remember, because we are dealing with length, there cannot be negative. So while normally we would get both +7 <em>and</em> -7, in this case we <em>only </em>get +7.

Now that we have the value of x, we can plug it into our original values.

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