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3 years ago

1. Mark ‘N’ if a wrong type of units is used. Mark ‘Y’ otherwise. (1 point each)

Engineering

1 answer:

maxonik [38]3 years ago

7 0

Answer:

bsbsdbsd

Explanation:

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A plate and frame heat exchanger has 15 plates made of stainless steel that are 1 m tall. The plates are 1 mm thick and 0.6 m wi

hodyreva [135]

Answer:

14.506°C

Explanation:

Given data :

flow rate of water been cooled = 0.011 m^3/s

inlet temp = 30°C + 273 = 303 k

cooling medium temperature = 6°C + 273 = 279 k

flow rate of cooling medium = 0.02 m^3/s

Determine the outlet temperature

we can determine the outlet temperature by applying the relation below

Heat gained by cooling medium = Heat lost by water

= ( Mcp ( To - 6 ) = Mcp ( 30 - To )

since the properties of water and the cooling medium ( water ) is the same

= 0.02 ( To - 6 ) = 0.011 ( 30 - To )

= 1.82 ( To - 6 ) = 30 - To

hence To ( outlet temperature ) = 14.506°C

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3 years ago

How to build a robot

Anuta_ua [19.1K]

Seriously? Ok

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build in the the shape of a robot, you can use a doll to help you if you are a beginner, but feel free to shape it the a Star Wars Character!

create an AI (now you said robot not AI) and fix everything up.

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4 years ago

Tech A states that friction brakes lose energy as heat. Tech B states that a brake-by-wire system converts this energy into usef

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3 years ago

Print the two strings, firstString and secondString, in alphabetical order. Assume the strings are lowercase. End with newline.

CaHeK987 [17]

Hai!

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3 years ago

9. An embankment having a volume of 320,000 yd is to be constructed from local borrow. The dry unit weight and moisture content

tatuchka [14]

Answer:

correct option is (B) 315,500

Explanation:

given data

volume = 320,000 yd³ = 8640000 ft³

dry unit weight = 106 pcf

moisture content = 18.2%

total unit weight = 122 pcf

moisture content = 16.7%

to find out

volume of borrow lyd needed

solution

first we get here weight of material that is

weight = volume × unit weight

weight = 8640000 × 122

weight = 1054080000 lb

that weight is weight of water + weight of solid so

0.167 × weight is weight of water + weight of solid ) = 1054080000 lb

and weight of solid = $\frac{1054080000}{1.167}$

weight of soil solid is = 903239075 pound

and weight of water = 150840925 pound

so volume of soil = 903239075 ÷ 106 lb/ft³ = 8521123.34 ft³

and volume required = 8521123.34 ft³ ÷ 27 ft³ = 315597.161 yd³

volume required = 315500 yd³

so correct option is (B) 315,500

3 0

3 years ago