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zhenek [66]
3 years ago
5

Initialize the tuple team_names with the strings 'Rockets', 'Raptors', 'Warriors', and 'Celtics' (The top-4 2018 NBA teams at th

e end of the regular season in order). Sample output for the given program:
Engineering
1 answer:
Drupady [299]3 years ago
4 0

Answer:

#Initialise a tuple

team_names = ('Rockets','Raptors','Warriors','Celtics')

print(team_names[0])

print(team_names[1])

print(team_names[2])

print(team_names[3])

Explanation:

The Python code illustrates or printed out the tuple team names at the end of a season.

The code displayed is a function that will display these teams as an output from the program.

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A 0.5m diameter sphere containing pollution monitoring equipment is dragged through the Charles River at a relative velocity of
Dmitriy789 [7]

Answer:

\phi = 155.57

Explanation:

from figure

taking summation of force in x direction be zero

\sum x = 0

F_D = Tsin \theta  .....1

\frac{c_d \rho v^2 A}{2} =Tsin \theta

taking summation of force in Y direction be zero

F_B - W-  Tcos \theta

T = \frac{F_B -W}{cos \theta} .........2

putting T value in equation 1

F_D - \frac{F_B -W}{cos \theta} sin\theta

F_D = \rho g V ( 1 -Sg) tan \theta.........3

F_D = \rho g [\frac{\pi d^3}{6}] ( 1 -Sg) tan \theta

tan \theta = \frac{6 c_D \rho v&2 A}{ 2 \rho g V \pi D^3 (1- Sg)}

Water at 10 degree C  has kinetic viscosity v = 1.3 \times 10^{-6} m^2/s

Reynold number

Re = \frac{ VD}{\nu} = \frac{10\times 0.5}{1.3 \times 10^{-6}} = 3.84 \times 10^6

so for Re =3.84 \times 10^6  cd is 0.072

tan \theta = \frac{3\times 0.072 \times 10^2 \times \pi \times 0.5^2}{ 2\times 9.81 \pi 0.5^3(1- 1.5)}

\theta = tan^{-1} [\frac{3\times 0.072 \times 10^2 \times \pi \times 0.5^2}{ 2\times 9.81 \pi 0.5^3(1- 1.5)}]

\theta = - 65.57 degree

\phi = 90 - (-65.57) = 1557.57 degree

8 0
3 years ago
A monatomic ideal gas undergoes a quasi-static process that is described by the function p(????)=p1+3(????−????1) , where the st
Alenkasestr [34]

A pure gas made up only of atoms. The noble gases argon, krypton, and xenon are some examples.

Concepts:

Perfect gas law: Work performed on the system: PV = nRT W = -∫PdV

Energy preservation formula: U = Q + W

Reasoning:

W = nRT ln(Vi/Vf) when the process is isothermal.

The temperature is said to be constant, and we are given n, Pfinal, and Vfinal.

Calculation information:

(A) A process that is isothermal has a constant temperature.

PV = nRT, and hence, constant

nRT = PV = 101000 Pa*25*10-3 m3

For a process that is isothermal, W = nRT ln(Vi/Vf).

W/(nRT)=3000 J/(101000 Pa*25*10-3 m3)=-1.19

(The gas produces -W of labor.)

Vi = (25*10-3 m3)/3.28 = 7.62*10-3 m3 = 7.62 L where Vf/Vi = exp(1.19) = 3.28 Vi (b) for a perfect gas PV = nRT. 101000 Pa*25*10-3 m3 = (8.31 J/K) T. T = 303.85 K.

To know more about process click here:

brainly.com/question/29310303

#SPJ4

5 0
1 year ago
Water flows through two smooth pipes with the same diameter and length as shown below. ipe is twice that through the first-pipe.
Alisiya [41]

Answer:

The right answer is (d)

Explanation:

The pressure drop in smooth pipes with laminar flow is determined by the resistance of the fluid to flow, which is controlled by Reynolds's number. At higher Re, higher drop. But in this case, we have no information about the speed of the fluid in each pipe, and the ipe is not related to that speed. therefore we don´t have the information to say that any of the other options are the right ones

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5Ea_b%20%7B7x%7D%20%5C%2C%20dx" id="TexFormula1" title="\int\limits^a_b {7x} \
Dafna11 [192]

Answer:

\frac{7}{2}a^2 - \frac{7}{2}b^2

Explanation:

\int\limits^a_b {7x} \, dx

=[\frac{7}{2}x^2]^a_b

=\frac{7}{2}a^2 - \frac{7}{2}b^2

5 0
3 years ago
A force is a push or pull in? A.a circle B.an arc C.a straight line
Salsk061 [2.6K]

Answer:

I think it is B: an arc

Explanation:

Hope this helps. Mark as brainiest

8 0
3 years ago
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