A 10.50 gram sample of a compound is decomposed to yield 3.40 g Na, 2.37 g S, and 4.73 g O. What is the mass percentage of each
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<u>Answer:</u>
<em>The number of moles of HCl actually present is 0.000988</em>
<u>Explanation:</u>
<em>The balanced chemical equation of the given reaction is </em>
Here one mole of HCl reacts with one mole of NaOH to form one mole of NaCl and one mole of water. Here the molarity of HCl is given as 0.026M.
<em>molarity of NaOH is 0.032M </em>
molarity is the number of moles per unit volume of solution.
we have to calculate the number of moles in 36 mL of HCl.
<em>38 mL=36/1000=0.038L </em>
<em>the number of moles in 38 mL of HCl is given by </em>
<em>no of moles =</em>