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soldier1979 [14.2K]
3 years ago
9

A porpoise sends out an ultrasonic burst and hears the echo off his favorite food in 0.13 seconds. How far away is the food sour

ce? Assume that sound travels at 1,530 m/sec in water.
Chemistry
1 answer:
aalyn [17]3 years ago
5 0

Answer:

The porpoise would hear its echo first because sound travels faster in water than in air. The bat would hear its echo first because the amplitude of sound waves ...

Explanation:

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You can practice converting between the mass of a solution and mass of solute when the mass percent concentration of a solution
vfiekz [6]

Answer:

450. g of 0.173 % KCN solution contains 779 mg of KCN.

Explanation:

Mass of the solution = m

Mass of the KCN in solution = 779 mg

Mass by mass percentage of KCN solution = 0.173%

(m/m)\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

0.173\%=\frac{779 mg}{m}\times 100

m=\frac{779 mg}{0.173}\times 100= 450,289 mg

1 mg = 0.001 g

m = 450,289 mg × 0.001 g = 450.289 mg ≈ 450. g

450. g of 0.173 % KCN solution contains 779 mg of KCN.

6 0
3 years ago
I NEED HELP PLEASE!!!! CHEMISTRY QUESTION: If 38 g of Li3P and 15 grams of Al2O3 are reacted, what total mass of products will r
maksim [4K]

Answer:

21.5 g.

Explanation:

Hello!

In this case, since the reaction between the given compounds is:

2Li_3P+Al_2O_3\rightarrow 3Li_2O+2AlP

We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:

n_{Li_3P}^{reacted}=38gLi_3P*\frac{1molLi_3P}{51.8gLi_3P}=0.73molLi_3P

Now, the moles of Li3P consumed by 15 g of Al2O3:

n_{Li_3P}^{consumed \ by \ Al_2O_3}=15gAl_2O_3*\frac{1molAl_2O_3}{101.96gAl_2O_3} *\frac{2molLi_3P}{1molAl_2O_3} =0.29molLi_3P

Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:

m_{Li_2O}=0.29molLi_3P*\frac{3molLi_2O}{2molLi_3P} *\frac{29.88gLi_2O}{1molLi_2O} =13gLi_2O\\\\m_{AlP}=0.29molLi_3P*\frac{2molAlP}{2molLi_3P} *\frac{57.95gAlP}{1molAlP} =8.5gAlP

Therefore, the total mass of products is:

m_{products}=13g+8.5g\\\\m_{products}=21.5g

Which is not the same to the reactants (53 g) because there is an excess of Li₃P.

Best Regards!

7 0
3 years ago
A reaction involves the parts of two compounds switching places to form two new compounds. What type of reaction is this?
In-s [12.5K]

Double Displacement would be correct

5 0
3 years ago
0.20dm
Alex_Xolod [135]

Answer:

I don't no sorry. ਕਿਉੁਂਕਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ 478figxigxurRyyv ਸ੍

5 0
3 years ago
What is the answer please
xeze [42]

Answer:

Selenium

Explanation:

Oxygen is present in the group sixteen.

This group consist of oxygen, sulfur, selenium, tellurium and polonium.

All of these have same number of valance electrons thus they show similar properties.

From the given list of elements only selenium is belong to oxygen family thus it has properties similar to the oxygen.

Electronic configuration of oxygen:

O = [He] 2s² 2p⁴

Electronic configuration of selenium:

Se = [Ar] 3d¹⁰ 4s² 4p⁴

While aluminium, boron and phosphorus are belongs to other groups that's why their properties are not similar to the phosphorus.

phosphorus is present in group 15.

Boron and aluminium are present in group 13.

6 0
4 years ago
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