Some of these frictions depend on the Pressure, temperature of atmosphere.
Static Friction: This is the friction force when two objects in contact are not moving relative to each other. This friction is higher than kinetic friction.
Kinetic or Dynamic friction: this the friction force opposing the motion of objects, when two objects in contact are in motion relative to each other. It is less than the static friction. The two surfaces are rubbing against each other as they move.
Rolling friction: This is the friction when two objects are in contact and one object is rolling over the other - like a wheel on a road. The point of contact appears as stationary. The rolling friction is very less compared to static friction & dynamic friction.
Lubricated friction: this is the friction between two solid surfaces in contact with a layer of lubricant fluid flowing in between them. This friction is the least.
Fluid friction - viscosity : this is friction between two adjacent layers that are moving relative to each other at different speeds in a fluid. This is not high.
Internal friction: when an object is compressed and forced to deform, like in a piece of rubber, there is friction between the layers, that opposes this deformation.
Skin friction is the friction that opposes movement of a fluid across a solid surface. This is also called drag. When a coin is dropped in water, there is a friction called drag on the coin. Same is the case when a ball is thrown, a drag is experienced by the ball due to the drag of air.
Answer:
Work done will be 78.76 J
Explanation:
We have given initial volume of the gas 
Pressure is given by 
Final volume 
Change in volume 
We know that work done is given by

Work done will be 78.76 J
Answer:
Explanation:
To detrmine the time interval at which the balls are in contact.
<u>Given information</u>
The mass of each steal ball 67.8g. The speed of ball towards each other is 4.80 m/s. The exerted force by each jaw 15.9 kN and the forece reduce the diameter by 0.130 mm.
Expression for the effective spring constant ball is shown below.
K = |F|/|x|
Here,
k is a spring constant
F is the force exerted on the ball
x is dispalcement due force
substitute 15.9 kN for F and 0.130 mm in above equation
<h2>K = (15.9 kN)(1X10³N)
/ (0.130 mm)(1x10⁻³m/1mm)</h2><h2>
122 x 10⁶ N/m</h2>
The spring constant is 122 x 10⁶ N/m
Answer:
I believe that the answer is 4
Explanation:
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