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xxTIMURxx [149]
3 years ago
15

A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collisi

on the green train moves with a speed of 3 m/s. What is the final momentum of the blue and green train combined?
A. 90 kgm/s
B. 110 kgm/s
C. 50 kgm/s
D. 200 kgm/s
Physics
2 answers:
Komok [63]3 years ago
8 0

Answer:

D. 200 kgm/s

Explanation:

Momentum is conserved.

Initial momentum = final momentum

(50 kg) (4 m/s) + (30 kg) (0 m/s) = final momentum

200 kgm/s = final momentum

irina1246 [14]3 years ago
7 0

Answer:

D. 200 kgm/s

Explanation:

A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collision the green train moves with a speed of 3 m/s. Therefore, the final momentum of the blue and green train combined is 200 kgm/s.

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malfutka [58]
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Rolling friction:  This is the friction when two objects are in contact and one object is rolling over the other - like a wheel on a road. The point of contact appears as stationary. The rolling friction is very less compared to static friction & dynamic friction.

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6 0
3 years ago
Consider a cylinder initially filled with 9.33 10-4 m3 of ideal gas at atmospheric pressure. An external force is applied to slo
Juli2301 [7.4K]

Answer:

Work done will be 78.76 J

Explanation:

We have given initial volume of the gas V_1=9.33\times 10^{-4}m^3

Pressure is given by P=1.013\times 10^5Pa

Final volume V_2=\frac{V_1}{6}=\frac{9.33\times 10^{-4}}{6}=1.555\times 10^{-4}m^3

Change in volume \Delta V=V_2-V_1=1.555\times 10^{-4}-9.33\times 10^{-4}=-7.775\times 10^{-4}m^3

We know that work done is given by

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8 0
3 years ago
Two identical steel balls, each of mass 67.8 g, are moving in opposite directions at 4.80 m/s.They collide head-on and bounce ap
xz_007 [3.2K]

Answer:

Explanation:

To detrmine the time interval at which the balls are in contact.

<u>Given information</u>

The mass of each steal ball 67.8g. The speed of ball towards each other is 4.80 m/s. The exerted force by each jaw 15.9 kN and the forece reduce the diameter by 0.130 mm.

Expression for the effective spring constant ball is shown below.

K = |F|/|x|

Here,

k is a spring constant

F is the force exerted on the ball

x is dispalcement due force

substitute 15.9 kN for F and 0.130 mm in above equation

<h2>K = (15.9 kN)(1X10³N) / (0.130 mm)(1x10⁻³m/1mm)</h2><h2>122 x 10⁶ N/m</h2>

The spring constant is 122 x 10⁶ N/m

     

4 0
3 years ago
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Gala2k [10]

Answer:

I  believe that the answer is 4

Explanation:

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