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Hunter-Best [27]
3 years ago
8

One hazard of space travel is the debris left by previous missions. There are several thousand objects orbiting Earth that are l

arge enough to be detected by radar, but there are far greater numbers of very small objects, such as flakes of paint. Calculate the force exerted by a 0.100-mg chip of paint that strikes a spacecraft window at a relative speed of 4.00×10^3 m/s, given the collision lasts 6.00×10^8s.
Physics
1 answer:
MariettaO [177]3 years ago
3 0

Answer:

F = 6666.7 N

Explanation:

Given that,

Mass of a chip, m = 0.1 mg

Initial speed, u = 0

Final speed,v=4\times 10^{3}\ m/s

Time of collision,t=6\times 10^{-8}\ s

We know that,

Force, F = ma

Put all the values,

F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.1\times 10^{-6}\times (4\times 10^3-0)}{6\times 10^{-8}}\\\\F=6666.7\ N

So, the required force is 6666.7 N.

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How are progression and variation similar?
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Two resistors of resistances R1 and R2, with R2>R1, are connected to a voltage source with voltage V0. When the resistors are
drek231 [11]

Answer:

r=0.127

Explanation:

When  connected in series

Current = I

When connected in parallel

Current = 10 I

We know that equivalent resistance

in parallel  R= R₁R₂/(R₂+ R₁)

In series  R = R₁+R₂

Given that voltage is constant (Vo)

We also know that relationship between voltage ,current and resistance  

V = I R

Vo = I (R₁+R₂)  ------------1

Vo = 10 I (R₁R₂/(R₂+ R₁)) -------2

From above equations

10 I (R₁R₂/(R₂+ R₁)) = I (R₁+R₂)  

10  R₁R₂ =  (R₁+R₂) (R₂+ R₁)

10  R₁R₂  = 2  R₁R₂  + R₁² + R₂²

8 R₁R₂  =     R₁² + R₂²

Given that

r =  R₁/R₂

Divides by R₂²

8R₁/R₂  = ( R₁/R₂)²+ 1

8 r = r ² + 1

r ² - 8 r+ 1 =0  

r= 0.127 and r= 7.87

But given that R₂>R₁  It means that r<1 only.

So the answer is r=0.127

8 0
3 years ago
A 1.0 kg ball and a 2.0 kg ball are connected by a 1.1-m-long rigid, massless rod. The rod is rotating cw about its center of ma
katen-ka-za [31]

The torque that will bring the balls to halt, t = 0.34 Nm

What is rotating?

In physics and mechanics, torque is the rotational equivalent of linear force. It is also referred to as the moment, moment of force, rotational force, or turning effect, depending on the field of study. It represents the capability of a force to produce a change in the rotational motion of the body.

Center of Mass of Rod = (1 * 0 + 2.0 * 1.1) /(1.0 + 2.0)

Center of Mass of Rod = 0.73 m

ω  = 21 rpm

ω = 21 * (2*pi)/60 rad/s

ω = 2.2 rad/s

Time to bring Halt = 5.2 s

Angular De-acceleration = 2.2/5.2 rad/s^2

α  =  0.423 rad/s^2

We know,

torque = (moment of inertia) * (angular acceleration)

t = I * α

Where

I = m1*r1^2 + m2*r2^2

I = 1kg * (0.73)^2 + 2kg * (1.1-0.73)^2

I = 0.8067 kg*m^2

Substituting Values -

torque = 0.8067  Kg*m^2 * 0.423 rad/s^2

torque = 0.34 N*m

The torque that will bring the balls to halt, t = 0.34 Nm

To learn more about the torque the link is given below:

brainly.com/question/18883167?

#SPJ4

7 0
1 year ago
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