Answer: Diagram B
Explanation:
A free body diagram shows the forces acting on an object in a certain scenario.
In this scenario there are two forces acting on the carrot: the Tension force (Ft) from the rope that the carrot is hanging from and Gravitational force(Fg) which is pulling the carrot to the Earth.
The diagram depicting this is diagram B.
Answer:
a) 3.0×10⁸ m
b) 0 m
Explanation:
Displacement is the distance from the starting position to the final position.
a) In half a year, the Earth travels from one point on the circle to the point on the exact opposite side of the circle (from 0° to 180°). The distance between the points is the diameter of the circle.
x = 2r
x = 2 (1.5×10⁸ m)
x = 3.0×10⁸ m
b) In a full year, the Earth travels one full revolution, so it ends up back where it started. The displacement is therefore 0 m.
Answer:<em> Option (D) is correct.</em>
Explanation:
Considering the hypothesis elaborated in this comprehension, it's given that areas that tend to lie near forest fires usually have extra positive strikes since smoke carries positively charged particles. In rudimentary term, this states that occurrence of positively charged particles will result in extra positive strikes.
Option (D) states that occurrence of extra positive strikes will be there even weeks after the charge of smoke particles have been dissociated.
Therefore this option, most seriously undermines the hypothesis.
Answer:
a mixture that can be separated
Answer:
0.247 J = 247 mJ
Explanation:
From the principle of conservation of energy, the workdone by the applied force, W = kinetic energy change + electric potential energy change.
So, W = ΔK + ΔU =1/2m(v₂² - v₁²) + q(V₂ - V₁) where m = mass of particle = 5.4 × 10⁻² kg, q = charge of particle = 5.10 × 10⁻⁵ C, v₁ = initial speed of particle = 2.00 m/s, v₂ = final speed of particle = 3.00 m/s, V₁ = potential at surface A = 5650 V, V₂ = potential at surface B = 7850 V.
So, W = ΔK + ΔU =1/2m(v₂² - v₁²) + q(V₂ - V₁)
= 1/2 × 5.4 × 10⁻²kg × ((3m/s)² - (2 m/s)²) + 5.10 × 10⁻⁵ C(7850 - 5650)
= 0.135 J + 0.11220 J
= 0.2472 J
≅ 0.247 J = 247 mJ
