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3 years ago

Bob travels 36m in 40seconds. How fast does he go?

Physics

2 answers:

Vesnalui [34]3 years ago

8 0

.9 meters a second
54 meters a minute
3.24 kilometers a hour

mylen [45]3 years ago

5 0

Answer:

<h2>0.9 Meters Per Second</h2><h2>54 Meters Per Minute</h2><h2>3.24 Kilometers Per Hour</h2>

Explanation:

Hope this helps! <3

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Beth has built a simple series circuit using wire, a battery, a lightbulb, and a switch. The bulb, however, does not light up wh

amid [387]

The right answer for the question that is being asked and shown above is that: "A. Reverse the way the wire is connected to the poles of the battery." the statement describes a step that will help troubleshoot and work toward the solution of this problem is that <span>Reverse the way the wire is connected to the poles of the battery.</span>

3 0

3 years ago

A 0.500-kg mass suspended from a spring oscillates with a period of 1.36 s. How much mass must be added to the object to change

lord [1]

The mass that must be added is 0.628 kg

Explanation:

The period of a mass-spring system is given by

$T=2\pi \sqrt{\frac{m}{k}}$

where

m is the mass

k is the spring constant

For the initial mass-spring system in the problem, we have

m = 0.500 kg

T = 1.36 s

Solving for k, we find the spring constant:

$k=(\frac{2\pi}{T})^2 m = (\frac{2\pi}{1.36})^2 (0.500)=10.7 N/m$

In the second part, we want the period of the same system to be

T = 2.04 s

Therefore, the mass on the spring in this case must be

$m=(\frac{T}{2\pi})^2 k =(\frac{2.04}{2\pi})^2 (10.7)=1.128 kg$

Therefore, the mass that must be added is

$\Delta m = 1.128 - 0.500 = 0.628 kg$

Learn more about period:

brainly.com/question/5438962

#LearnwithBrainly

5 0

4 years ago

John(body mass=160pounds) is taking off for a long jump. The average ground reaction force Fg at takeoff is 1400 N pointing forw

slega [8]

Answer:

The free body diagram of John is shown in the attached figure (in the FBD john's mass is supposed to be concentrated at his center of mass and FBD is made of center of mass)

b) As shown in the FBD the ground reaction forces are:

i) In X direction $F_{x}=1400cos(35^{o})=1146.81N$

ii) In Y direction $F_{y}=1400sin(35^{o})=803.0N$

c) The respective accelerations in x and y direction's is calculated by newton's second law as indicated under

$\sum F_{x}=ma_{x}\\\\\therefore a_{x}=\frac{\sum F_{x}}{m}=\frac{1146.8N}{72.57kg}=15.80m/s^{2}\\\\\sum F_{y}=ma_{y}\\\\\therefore a_{y}=\frac{\sum F_{y}}{m}=\frac{803.00-72.57\times 9.81}{72.57}=1.255m/s^{2}$

4 0

3 years ago

Convert 1.5 radian into milliradians.

Alex

Answer:

1500 milliradians

Explanation:

Data provided in the question:

1.5 radians

Now,

1 radians consists of 1000 milliradians

1 milli = 1000

thus for the 1.5 radians, we have

1.5 radians = 1.5 multiplied by 1000 milliradians

1.5 radians = 1500 milliradians

Hence, after the conversion

1.5 radians equals to the value 1500 milliradians

4 0

3 years ago

1) A 1,600 kilogram car is also traveling in a straight line. Its momentum is 32,500 kg*m/s. What is the

BaLLatris [955]

Answer:

v = 20.31 m/s

Explanation:

p = mv -> v = p/m = 32,500 kg*m/s / 1,600 kg = 20.31 m/s

4 0

3 years ago