2 years ago

1) A 1,600 kilogram car is also traveling in a straight line. Its momentum is 32,500 kg*m/s. What is the

Physics

1 answer:

BaLLatris [955]2 years ago

4 0

Answer:

v = 20.31 m/s

Explanation:

p = mv -> v = p/m = 32,500 kg*m/s / 1,600 kg = 20.31 m/s

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A proton accelerates from rest in a uniform electric field of 680 N/C. At one later moment, its speed is 1.30 Mm/s (nonrelativis

Ksivusya [100]

Answer:

Acceleration, $a=6.51\times 10^{10}\ m/s^2$

Explanation:

Given that,

Electric field, E = 680 N/C

Speed of the proton, v = 1.3 Mm/s

We need to find the acceleration of the proton. We know that the force due to motion is balanced by the electric force as :

$qE=ma$

a and m are the acceleration and mass of the proton.

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$a=\dfrac{1.6\times 10^{-19}\times 680}{1.67\times 10^{-27}}$

$a=6.51\times 10^{10}\ m/s^2$

So, the acceleration of the proton is $a=6.51\times 10^{10}\ m/s^2$ . Hence, this is the required solution.

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abruzzese [7]

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Answer:

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