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Ber [7]
3 years ago
10

Convert 1.5 radian into milliradians.

Physics
1 answer:
Alex3 years ago
4 0

Answer:

1500 milliradians

Explanation:

Data provided in the question:

1.5 radians

Now,

1 radians consists of  1000 milliradians

1 milli = 1000

thus for the 1.5 radians, we have

1.5 radians = 1.5 multiplied by 1000 milliradians

or

1.5 radians = 1500 milliradians

Hence, after the conversion

1.5 radians equals to the value 1500 milliradians

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A diver shines a flashlight upward from beneath the water (n=1.33) at a 36.2° angle to the vertical. At what angle does the ligh
horrorfan [7]

Answer:

The flashlight leaves the water at an angle of 51.77°.

Explanation:

if n1 = 1.33 is the refractive index of water and ∅1 is the angle at which the flashlight shine beneath the water, and n2 = 1.0 is the refractive index of air and ∅2 is the angle the flashlight leaves the water.

Then, according to Snell's law :

n1×sin(∅1) = n2×sin(∅2)

sin(∅2) = n1×sin(∅1)/n2

           = (1.33)×sin(36.2)/(1.0)

           = 0.7855055×379

     ∅2 = 51.77°

Therefore, the flashlight leaves the water at an angle of 51.77°.

7 0
4 years ago
What is the best example of the purpose of scientific notation?
Gemiola [76]

The correct answer would be to express large and small numbers.


3 0
3 years ago
this is energy that is transferred by the movement of electrons through a conductor the electrons create circuit
Paha777 [63]
The correct answer for this question is this one: "Potential Energy." 
Potential energy is the energy that is transferred by the movement of electrons through a conductor the electrons create circuit. It is energy at moving. Hope this helps answer your question and have a nice day ahead.
7 0
3 years ago
Que fracción de luz que llega directa a una lamina de vidrio se refleja en la primera superficie?
Veseljchak [2.6K]

Answer:

unos 40 o30 pienso

Explanation:

7 0
3 years ago
A 64.1 kg runner has a speed of 3.10 m/s at one instant during a long-distance event.(a) What is the runner's kinetic energy at
Liono4ka [1.6K]

Answer:

(a)  the runner's kinetic energy at the given instant is 308 J

(b)  the kinetic energy increased by a factor of 4.

Explanation:

Given;

mass of the runner, m = 64.1 kg

speed of the runner, u = 3.10 m/s

(a) the kinetic energy of the runner at this instant is calculated as;

K.E_i = \frac{1}{2} mu^2\\\\K.E_i = \frac{1}{2}  \times 64.1 \times 3.1^2\\\\K.E_i = 308 \ J

(b) when the runner doubles his speed, his final kinetic energy is calculated as;

K.E_f = \frac{1}{2} mu_f^2\\\\K.E_f = \frac{1}{2} m(2u)^2\\\\K.E_f = \frac{1}{2} \times 64.1 \ \times (2\times 3.1)^2\\\\K.E_f = 1232 \ J

the change in the kinetic energy is calculated as;

\frac{K.E_f}{K.E_i} = \frac{1232}{308} =4

Thus, the kinetic energy increased by a factor of 4.

4 0
3 years ago
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