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4 years ago

Match each wave interaction to the correct description.

Physics

2 answers:

Nadya [2.5K]4 years ago

4 0

Answer:

See attachment

Explanation:

daser333 [38]4 years ago

3 0

Answer:

reflection-bouncing of a wave after it hits an object (Like sound)

refraction-bending of a wave as it passes through mediums (Stick you hand in the water and see it refract)

transmission-passing of a wave through an object

absorption- taking in of a wave by an object as the wave hits it

diffraction- bending and scattering of a wave as it hits an object or opening

I got it right on EDG Completely agree with the other answer.

Explanation:

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What is the x-component of the force on the charge located at x = 8 cm given that q = 1.1 μC in N?

jonny [76]

Answer:

Answer is = 12.3 x 10^6 N

Explanation:

We need to calculate force on the charge which is in Newtons:

Formula is = K q1q2/r^2

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4 years ago

A scientific hypothesis can become a theory if....

Vadim26 [7]

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3 years ago

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Which choice most accurately defines resistance and voltage of a circuit?

devlian [24]

Answer:

Explanation:

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3 years ago

A block of mass m is at rest at the origin at t=0. It is pushed with constant force F0 from x=0 to x=Lacross a horizontal surfac

Tomtit [17]

Answer:

A) v = √[(F₀/m - μ₀) 2x + x2 / L] , b) v = √[2 (F₀ / m - μ₀) +1] L

Explanation:

For this exercise we will use Newton's second law

X axis

Fo - fr = ma

Y Axis

N - W = 0

N = mg

The equation for the force of friction is

fr = μ N

.fr = μ mg

Let's replace

Fo - μ mg = m a

a = Fo / m - μ g

They ask us the speed of the block, so we must use

a = dv / dt = dv/dx dx dt = dv/dx v

v dv = a dx

We replace

v dv = (F₀ / m - μ₀ (1- x/L)) dx

We integrate

∫v dv = F₀ / m ∫ dx - μ₀ ∫ dx + 1 / L ∫ x dx

½ v² = (F₀ / m - μ₀) x + 1 / L x² / 2

We evaluate from the lower limit, for x = 0 the speed is zero v = 0, to the upper limit x, v

½ v² = (F₀ / m - μ₀) x + 1 / 2L x²

v = √[(F₀ / m - μ₀) 2x + x2 / L]

Part B

The velocity for x = L

v = √(F₀ / m - μ₀) 2L + L2 / L

v = √[2 (F₀ / m - μ₀) +1] L

8 0

3 years ago

An audio amplifier provides an alternating rms emf of 15.0V a loudspeaker connected to the amplifier has a resistance of 10.4 w

Margarita [4]

Answer:

Current in the speaker will be 1.442 A

Explanation:

We have given an audio amplifier of rms emf of 15 volt

So emf of the audio amplifier $V=15volt$

Resistance of the amplifier $R=10.4ohm$

We have to find the current

From ohm's ;aw we know that V = IR , here I is current and R is resistance

So $15=I\times 10.4$

I = 1.442 A

So current in the speaker will be 1.442 A

4 0

3 years ago