<u>Answer:</u> The mass of ice cube is 77.90 grams
<u>Explanation:</u>
When ice is mixed with water, the amount of heat released by ice will be equal to the amount of heat absorbed by water.

The equation used to calculate heat released or absorbed follows:

......(1)
where,
= mass of ice = ? g
= mass of water = 30.0 g
= final temperature = 19.5°C
= initial temperature of ice = 0.0°C
= initial temperature of water = 45.0°C
= specific heat of ice = 2.108 J/g°C
= specific heat of water = 4.186 J/g°C
Putting values in equation 1, we get:
![m_1\times 2.108\times (19.5-0)=-[30.0\times 4.186\times (19.5-45.0)]](https://tex.z-dn.net/?f=m_1%5Ctimes%202.108%5Ctimes%20%2819.5-0%29%3D-%5B30.0%5Ctimes%204.186%5Ctimes%20%2819.5-45.0%29%5D)

Hence, the mass of ice cube is 77.90 grams
Answer: C
Explanation:
For this problem, we would use Charles's Law. We fill in what we are given and solve.
Charles's Law: 



Answer:
If 700 g of water at 90 °C loses 27 kJ of heat, its final temperature is 106.125 °C
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
In this way, between heat and temperature there is a direct proportional relationship (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also increases; and the same happens when either of the two decreases .). The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:
Q = c * m * ΔT
Where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature, ΔT= Tfinal - Tinitial
In this case:
- Q= 27 kJ= 27,000 J (being 1 kJ=1,000 J)

- m=700 g
- ΔT= Tfinal - Tinitial= Tfinal - 90 °C
Replacing:

Solving:


16.125 °C= Tfinal - 90 °C
Tfinal= 16.125 °C + 90 °C
Tfinal= 106.125 °C
<u><em>If 700 g of water at 90 °C loses 27 kJ of heat, its final temperature is 106.125 °C</em></u>