It would be 35.8 Calories or calories. Not sure about that part. Hope this helps though.
Answer:
Explanation:
L
=
1.10
L
of solution
Explanation:
The Molarity
M
is calculated by the equation comparing moles of solute to liters of solution
M
=
m
o
l
L
For this question we are given the Molarity 0.88M
We are told the solute is a 25.2 gram sample of LiF, Lithium Fluoride
We can convert the mass of LiF to moles by dividing by the molar mass of LiF
Li = 6.94
F = 19.0
LiF = 25.94 g/mole
25.2
g
r
a
m
s
x
1
m
o
l
25.94
g
r
a
m
s
=
0.97
moles
Now we can take the the molarity and the moles and calculate the Liters of solution
M
=
m
o
l
L
M
L
=
m
o
l
L
=
m
o
l
M
L
=
0.97
m
o
l
0.88
M
L
=
1.10
L
of solution i just did look at my papaer
Answer:
There are 3 steps of this problem.
Explanation:
Step 1.
Wet steam at 1100 kPa expands at constant enthalpy to 101.33 kPa, where its temperature is 105°C.
Step 2.
Enthalpy of saturated liquid Haq = 781.124 J/g
Enthalpy of saturated vapour Hvap = 2779.7 J/g
Enthalpy of steam at 101.33 kPa and 105°C is H2= 2686.1 J/g
Step 3.
In constant enthalpy process, H1=H2 which means inlet enthalpy is equal to outlet enthalpy
So, H1=H2
H2= (1-x)Haq+XHvap.........1
Putting the values in 1
2686.1(J/g) = {(1-x)x 781.124(J/g)} + {X x 2779.7 (J/g)}
= 781.124 (J/g) - x781.124 (J/g) = x2779.7 (J/g)
1904.976 (J/g) = x1998.576 (J/g)
x = 1904.976 (J/g)/1998.576 (J/g)
x = 0.953
So, the quality of the wet steam is 0.953
Answer:
<h2>The answer is 35 mL</h2>
Explanation:
Density of a substance can be found by using the formula
From the question we are finding the amount of space the gas will occupy that's the volume of the gas
Making volume the subject we have
From the question
mass = 23.8 g/mL
Density = 0.68 g/mL
Substitute the values into the above formula and solve
That's
We have the final answer as
<h3>35 mL</h3>
Hope this helps you
