Answer:
The first 2 statements are correct. The others are false.
If Ca(CH3COO)2 is added, the pH becomes more basic.
If a small amount of HCl is added, the pH becomes slightly more acidic.
Explanation:
Step 1: Data given
Molarity of a CH3COOH solution = 0.10 M
⇒CH3COOH is a weak acid
Molarity of a NaCH3COO solution = 0.20 M
Step 2: If Ca(CH3COO)2 is added, the pH becomes more basic.
Ca(CH3COO)2 → Ca^2+ + 2CH3COO-
This means when we add Ca(CH3COO)2, the amount of CH3COO- will be increased.
CH3COO- is the conjugate base of the acid CH3COOH.
By increasing the amount of the conjugate base CH3COO- the pH will become more basic.
The first statement is true.
Step 3: If a small amount of HCl is added, the pH becomes slightly more acidic
This is true. By adding a strong acid, the pH will become more acid.
Step 4: If HCl is added, the H ions react with the CH3COOH.
When the strong acid HCl is added. The H+ ions will react with a negative charged compound. This will not be CH3COOH but it's conjugate base CH3COO-
This statement will be false.
Step 5: If a small amount of NaOH is added, the pH becomes slightly more acidic.
When we add HCl, ste pH will become more acid. NaOH is a strong base. When adding a strong base, the pH will become (slightly) more basic, not more acid.
This statement is false.
Step 6: If NaOH is added, the OH- ions react with the CH3COO- ions.
The OH- ions of NaOH are negative charged, they will not react with the CH3COO- ions because those are also negative charged.
This statement is false?
The first 2 statements are correct. The others are false.
If Ca(CH3COO)2 is added, the pH becomes more basic.
If a small amount of HCl is added, the pH becomes slightly more acidic.