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Nina [5.8K]
3 years ago
5

Which of the following displays the correct change in enthalpy and best describes the reaction below? 2CsCl(aq) + Na2SO4(aq) 2Na

Cl(aq) + Cs2SO4(aq) Given: Cs2SO4: ∆H= -1400 kJ CsCl: ∆H= -415 kJ Na2SO4: ∆H= -1380 kJ NaCl: ∆H = -411 kJ
https://gyazo.com/bb924c15fe3b2c341d56dcb96b91658c
Chemistry
1 answer:
Bond [772]3 years ago
3 0
We subtract the enthalpies of the reactants from that of the products:
2\Delta
 H(NaCl)+\Delta H(Cs_2 SO_4)-2\Delta H(CsCl)-\Delta H(Na_2 SO_4) \\ 
=2(-411)+(-1400) -2(-415)-(-1380) \\ = -12 kJ
Since this is < 0, this is an exothermic reaction.

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