What do the elements in each pair have in common?

The large holes that can form in Limestone eventually lead to the formation of caves and caverns.

forsale [732]

Answer:
True
Explanation:
Because it would be false That Caves and caverns are common in dry regions where these is a layer of limestone near the surface.

3 0

3 years ago

Helppppppppppppppppppppppp

arsen [322]

ITS CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC

8 0

3 years ago

Xco3 enter the group number of x

Mademuasel [1]

We know that C has a formal charge of +4 while each O element has a formal charge of -2, therefore the formal charge of X is:

X + 2 – 2 * 3 = 0

X + 2 – 6 = 0

X = 4

<span>So X has a group number of 4.</span>

4 0

3 years ago

When hcl(aq) and naoh(aq) are mixed in a beaker, the beaker feels warm to the touch. what is known about the enthalpy of this re

Nady [450]

The balanced chemical equation representing the neutralization reaction of hydrochloric acid (HCl) and sodium hydroxide (NaOH),

$HCl (aq) + NaOH(aq) ---> NaCl(aq) + H_{2}O(l) + Heat$

This reaction is exothermic that is it proceeds by the release of heat energy. This heat energy is lost to the surroundings. This is the reason for the warming up of the beaker where the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) takes place. The enthalpy of such reaction will be negative as the reaction is exothermic.

5 0

3 years ago

Given the following values for the change in enthalpy (deltaH) and entropy (deltaS), which of the following processes can occur

Shtirlitz [24]

Answer:

Option A and B

Explanation:

(a) DeltaH = -84 kj mol-2 (-20 kcal mol-1), DeltaS = +125j mol-2K-1)(+30 cal mol-1 K-1)

Delta G = Delta H – T * DS

Substituting the given values, we get –

Delta G = -84 -298 *(125/1000) = -121.25 KJ/mol

Delta G is negative hence the process is spontaneous and will not violate the second law of thermodynamics

(b) DeltaH = -84 kj mol-2 (-20 kcal mol-1), DeltaS = -125j mol-2K-1)(-30 cal mol-1 K-1)

Delta G =-84 -298 *(-125/1000) = -46.75 KJ/mol

Delta G is negative hence the process is spontaneous and will not violate the second law of thermodynamics

(c) DeltaH = +84 kj mol-2 (+20 kcal mol-1), DeltaS = +125j mol-2K-1)(+30 cal mol-1 K-1)

Delta G = 84 -298 *(125/1000) = +46.75 KJ/mol

Delta G is positive hence the process is non-spontaneous and will violate the second law of thermodynamics

(d) DeltaH = +84 kj mol-2 (+20 kcal mol-1), DeltaS = +125j mol-2K-1)(-30 cal mol-1 K-1)

Delta G = 84 -298 *(-125/1000) = + 121.25 KJ/mol

Delta G is positive hence the process is non-spontaneous and will violate the second law of thermodynamics

6 0

3 years ago