Boiling point<span> is the </span>temperature<span> at which the vapor pressure of the liquid equals the surrounding pressure.
Above boiling point point, liquid get converted into vapour.
Now, boiling point of water is 100 oC at room pressure. Room pressure is equal to 760 torr. Thus, at 100 oC, vapour pressure of water becomes equal to 760 torr.
Now, if external pressure is increased to 880 torr, more heat is to be supplied so that vapour pressure of water equals 880 torr.
So, at 880 torr, boiling point of water will be more than 100 oC. In present case, most like the boiling point of water is equal to 105 oC.
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I couldn't find the answer to your question.
I think the answer is B . I really hope that this helps you out.
Answer:
89 L
Explanation:
Step 1: Given data
- Initial pressure (P₁): 0.97 atm
- Initial volume (V₁): 105 L
- Initial temperature (T₁): 318 K
- Final pressure (P₂): 1.05 atm
- Final temperature (T₂): 293 K
Step 2: Calculate the final volume of the weather balloon
If we assume that the gas inside the balloon behaves as an ideal gas, we can calculate the final volume of the gas using the combined gas law.
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
V₂ = P₁ × V₁ × T₂ / T₁ × P₂
V₂ = 0.97 atm × 105 L × 293 K / 318 K × 1.05 atm = 89 L
