Fc=mv2/r formula of centripetal force will be applied here with radius mass and velocity described in the above question
<span>5.3 m/s
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The formula for Kinetic Energy is:
KE = 1/2mv^2
So, KE = 1/2(500)(10)^2
KE = 1/2(500)(100)
KE = 1/2(50000)
KE = 25,000 J
A) Equivalent Resistance= (1/25+1/55+1/75)^-1=14.0ohms(3s.f.)
b) Current=9.0V/14.0=0.644A(3s.f.)
c) Current through 25-resistor=9/25=0.360A
Current through 55-resistor=9/55=0.164A
Current through 75-resistor=9/75=0.120A
All answers are rounded off to 3 significant figures
Answer:
Explanation:
cSep 20, 2010
well, since player b is obviously inadequate at athletics, it shows that player b is a woman, and because of this, she would not be able to hit the ball. The magnitude of the initial velocity would therefore be zero.
Anonymous
Sep 20, 2010
First you need to solve for time by using
d=(1/2)(a)(t^2)+(vi)t
1m=(1/2)(9.8)t^2 vertical initial velocity is 0m/s
t=.45 sec
Then you find the horizontal distance traveled by using
v=d/t
1.3m/s=d/.54sec
d=.585m
Then you need to find the time of player B by using
d=(1/2)(a)(t^2)+(vi)t
1.8m=(1/2)(9.8)(t^2) vertical initial velocity is 0
t=.61 sec
Finally to find player Bs initial horizontal velocity you use the horizontal equation
v=d/t
v=.585m/.61 sec
so v=.959m/s