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4 years ago

A leopard of mass 65kg climbs 7m up a tall tree. Calculate how much gravitational potential energy it gains. Assume g=10N/kg.

Physics

1 answer:

vesna_86 [32]4 years ago

8 0

Answer: 4550 Joules

The formula for potential energy in gravitational field is as follows:

$E_{pot} = mgh=65kg \cdot 10 \frac{N}{kg} \cdot 7m = 4550 J$

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Type of energy transformed into chemical energy by plants is called type of energy transformed into chemical energy by plants is

yuradex [85]

I think the correct answer is light energy. It is light energy that is transformed into chemical energy by plants by the process called photosynthesis. In this process, plants take in water, carbon dioxide, and sunlight and turn them into glucose and oxygen.

6 0

3 years ago

A mass on a

andrew-mc [135]

Answer:

S = 2 * pi * 1 m = 6.28 m = distance traveled

V = S / T or T = S / V = 6.28 m / 5 m/s = 1.26 sec

This will be the time for 1 revolution or the period of the motion.

5 0

3 years ago

Calculate the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal. Assume that the spe

goblinko [34]

Answer:

the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal is 1835.16 .

Explanation:

We know, wavelength is expressed in terms of Kinetic Energy by :

$\lambda=\dfrac{h}{\sqrt{2mE}}$

Therefore , $E=\dfrac{h^2}{2 \lambda^2 m}$

It is given that both electron and proton have same wavelength.

Therefore,

$E_e=\dfrac{h^2}{2 \lambda^2 m_e}$ .... equation 1.

$E_p=\dfrac{h^2}{2 \lambda^2 m_p}$ .... equation 2.

Now, dividing equation 1 by 2 .

We get ,

$\dfrac{E_e}{E_p}=\dfrac{\dfrac{h^2}{2 \lambda^2 m_e}}{\dfrac{h^2}{2 \lambda^2 m_p}}\\\\\\\dfrac{E_e}{E_p}=\dfrac{m_p}{m_e}$

Putting value of mass of electron = $9.1\times 10^{-31}\ kg$ and mass of proton = $1.67\times 10^{-27}\ kg.$

We get :

$\dfrac{E_e}{E_p}=\dfrac{1.67\times 10^{-27}\ kg}{9.1\times 10^{-31}\ kg}=1835.16$

Hence , this is the required solution.

4 0

4 years ago

Read 2 more answers

A car traveling 36 mi/h accelerates uniformly

iren2701 [21]

First convert from mi/h to ft/s. There are 5280 ft to 1 mi, and 3600 s to 1 h, so

36 mi/h = (36 mi/h) * (5280 ft/mi) * (1/3600 h/s) = 52.8 ft/s

Let a be the acceleration of the car. The car's speed at time t is

v = 52.8 ft/s + a t

so that after 5.4 s, it attains a speed of

v = 52.8 ft/s + (5.4 s) a

Recall that

v² - u² = 2 a ∆x

where u is the car's initial velocity and ∆x is the distance it's traveled.

We have

(52.8 ft/s + (5.4 s) a)² - (52.8 ft/s)² = 2 a (595 ft)

Omitting units, this equation reduces to

(52.8 + 5.4 a)² - 52.8² = 1190 a

==> 29.16 a² - 619.76 a = 0

==> 29.16 a - 619.76 = 0

==> 29.16 a = 619.76

==> a ≈ 21.25 ft/s²

7 0

3 years ago

How would you go about measuring the speed of a vehicle? What measurements would you have to take? What calculations would you h

White raven [17]

Answer:

For a body moving at a uniform velocity you can calculate the speed by dividing the distance traveled by the amount of time it took, for example one mile in 1/2 hour would give you 2 miles per hour. If the velocity is non-uniform all you can say is what the average speed is.

3 0

3 years ago