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3 years ago

A leopard of mass 65kg climbs 7m up a tall tree. Calculate how much gravitational potential energy it gains. Assume g=10N/kg.

Physics

1 answer:

vesna_86 [32]3 years ago

8 0

Answer: 4550 Joules

The formula for potential energy in gravitational field is as follows:

$E_{pot} = mgh=65kg \cdot 10 \frac{N}{kg} \cdot 7m = 4550 J$

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An oil layer that is 5.0 cm thick is spread smoothly and evenly over the surface of water on a windless day. A light ray from th

marshall27 [118]

Answer:

The angle of refraction in water 32.12°.

Explanation:

Given that,

Thickness = 5.0 cm

Index of refraction for oil = 1.15

Index of refraction for water = 1.33

Angle = 45°

We need to calculate the angle of refraction

When the ray of light enters from air to oil

Using formula of refraction

$n_{a}\sin\theta_{a}=n_{o}\sin\theta_{o}$

Where, $n_{a}$ = refractive index of air

$n_{0}$ = refractive index of oil

Put the value into the formula

$1\times\sin45=1.15\sin\theta_{o}$

$\sin\theta_{o}=\dfrac{1}{\sqrt{2}\times1.15}$

$\sin\theta_{o}=0.6148$

$\theta_{o}=sin^{-1}0.6149$

$\theta_{o}=37.94^{\circ}$

When the ray of light enters from oil to water

Using formula of refraction

$n_{0}\sin\theta_{0}=n_{w}\sin\theta_{w}$

Where, $n_{w}$ = refractive index of water

$1.15\times\sin37.94^{\circ}=1.33\sin\theta_{w}$

$\sin\theta_{w}=\dfrac{1.15\sin37.94^{\circ}}{1.33}$

$\theta_{w}=\sin^{-1}0.53163$

$\theta_{w}=32.12^{\circ}$

Hence, The angle of refraction in water 32.12°.

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