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Snowcat [4.5K]
4 years ago
9

If you are traveling in a primary channel and you encounter a red and green marker (with the green band on top) when proceeding

in an upstream direction, what must you do
Physics
1 answer:
lisov135 [29]4 years ago
5 0
There are many indicators used in navigation such as international markers in order to understand quickly the directions intended during sailing. For example, a green marker indicates that you must pass on the side such that the green marker will be on your left side while the red marker means that the marker should be on your right side on the other hand upon passing the marker. Now when there is a green and red marker, this means you can either pass on either sides but the recommended channel is the direction indicated by the color of topmost band. If green, the navigator must work so that the passing makes the marker on the left side.
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A tiger leaps horizontally from a 5.7m high rock with a speed of 4.0 m/s. How far from the base of the rock will she land?
kati45 [8]

Answer:

4.3 meters

Explanation:

See attached picture.

8 0
3 years ago
190 kg of water is to be raised by a water pump to a height of 25 meters from the bottom of a well in 60 seconds. What should be
ladessa [460]

Answer:

776.6 w

1.04 hp

Explanation:

given:

Mass, m = 190kg

height change, h = 25m

time elapsed, t = 60 s

acceleration due to gravity, g = 9.81 m/s²

Potential energy required raising 190 kg of water to a height of 25m

= mgh

= 190 x 9.81 x 25

= 46,597.5 J

Power required in 60 s

= Energy required ÷ time elapsed

= 46,597.5 ÷ 60

= 776.6 Watts  (Use conversion 1 W = 0.00134102 hp)

= 776.6 w x 0.00134102 hp/w

= 1.04 hp

6 0
3 years ago
Jogger A has a mass m and a speed v, jogger B has a mass m/2 and a speed 3v, jogger C has a mass 3m and a speed v/2, and jogger
finlep [7]

Answer: B>A=D>C

Explanation:

Kinetic Energy is the product of mass and square of the velocity

For Jogger A

K.E._a=\frac{1}{2}mv^2

For Jogger B

K.E._b=\frac{1}{2}\times\frac{m}{2}\times(3v)^2=\frac{9}{4}mv^2\\K.E._b=2.25mv^2

For Jogger C

K.E._c=\frac{1}{2}\times3m\times(\frac{v}{2})^2=\frac{3}{8}mv^2\\K.E._c=0.375mv^2

For Jogger D

K.E._d=\frac{1}{2}\times4m\times(\frac{v}{2})^2=\frac{1}{2}mv^2

Kinetic Energy of Joggers in increasing order

B>A=D>C

8 0
3 years ago
Draw the vector c⃗ =1.5a⃗ −3b⃗
Debora [2.8K]
<span>The magnitude of a is 1.5
The magnitude of b is -3
The magnitude of the vector is
</span>√(1.5² + (-3)²) = 3.35
<span>The angle is
</span>θ = tan⁻¹ (-3/1.5) = 63.43°
<span>The vector is drawn with a magnitude of 3.35 and an angle of 63.43</span>°.
3 0
4 years ago
How is thermal energy from the sun distributed on Earth ?
Mrac [35]
Conduction and convection both require some material substance
to move heat from one place to another, and there's none of that
between the sun and Earth. 

The only way for thermal energy to move from place to place with
nothing in between is by the process of radiation, and that's how
it gets here from the sun.
3 0
3 years ago
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