It should be 95,040. On the first day, you have 12 choices. On the second, eleven, and so on, until day 5. 12x11x10x9x8.
480/6<span> = 80ft </span>7<span> x 80 = 560ft.</span>
Answer:
Shortest side = 39 cm.
Median side = 65 cm.
Longest side = 91 cm.
Step-by-step explanation:
The perimeter in total is 195 cm. The ratio of the sides are 3 : 5 : 7.
First, find how much parts there are as a whole, by combining the ratios:
3 + 5 + 7 = 15 parts.
Divide the total of parts from the total measurement:
195/15 = 13
Each part has the measurement of 13 cm.
1 part = 13 cm.
Use the following ratio to solve for each of the sides:
Shortest side: 3
3 x 13 = 39
Shortest side = 39 cm.
Median side: 5
5 x 13 = 65
Median side = 65 cm.
Longest side: 7
7 x 13 = 91
Longest side = 91 cm.
Check. Combine all side measurements together. They should equal 195:
39 + 65 + 91 = 195
(39 + 65) + 91 = 195
(104) + 91 = 195
195 = 195 (True).
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Answer:
There were 6 benches in park 1 and 18 benches in park 2.
Step-by-step explanation:
Let x be the no of benches in Park 1 and y in park 2.
Given that there are 12 more benches in park 2 than 1
Writing this in equation form, we have y = x+12 ... i
Next is if 2 benches were transferred from park 2 to park 1, then we have
x+2 in park 1 and y-2 in park 2.
Given that y-2 = twice that of x+2
Or y-2 = 2x+4 ... ii
Rewrite by adding 2 to both sides of equation ii.
y = 2x+6 ... iii
i-iii gives 0 = -x+6
Or x =6
Substitute in i, to have y = 6+12 = 18
Verify:
Original benches 6 and 18.
18 = 6+12 hence I condition is satisfied
18-2 = 2(6+2)
II is also satisfied.
Answer:
w ≤ 593
Step-by-step explanation:
Missing option;
w ≥ 593
w > 593
w ≤ 593
593 < w
Explanation:
w ≥ 593 No
Number of wrapping paper sold never be more than 593.
w > 593 no
Number of wrapping paper sold never be more than 593.
w ≤ 593 yes
Number of wrapping paper sold will be equal or less than 593.
