Answer:
Force on each front wheel = 4711 N
Force on each back wheel = 2591 N
Explanation:
Weight of car = 1490 Kg
Distance of COG from front axle= 1.1 m
Distance of COG from back axle = 3.1 - 1.1 = 2 m
Vertical forces are balanced ,
So, R1 + R2 = mg
R1 + R2 = 1490× 9.8
Thus; R1 + R2 = 14602 - - - eq1
Where
R1 is force on front wheel
R2 is force on back wheel
Now, we know that;
Angular momentum about centre of gravity is zero.
Therefore,
R1 × 1.1 = R2 × 2
R1 = (2/1.1)R2
Put this into equation1, to get;
(2/1.1)R2 + R2 = 14602
R2(2.818) = 14602
R2 = 14602/2.818
R2 = 5182 N and R1 = (2/1.1)5182 = 9422 N
Hence, force on each back wheel = R2/2 = 5182/2 = 2591 N
Force on each front wheel = R1/2 = 9422/2 = 4711 N
