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tatuchka [14]
4 years ago
8

A device has power -2 D . The device is

Physics
1 answer:
slavikrds [6]4 years ago
7 0

Answer:

b.

Explanation:

-vesign shows the lens is <em><u>C</u></em><em><u>O</u></em><em><u>N</u></em><em><u>C</u></em><em><u>A</u></em><em><u>V</u></em><em><u>E</u></em>

<em><u>f</u></em><em><u>=</u></em>1/power

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Water flows in a horizontal pipe of length L. At the midpoint L/2, the pipe diameter changes. On one side of the midpoint, the p
andrew-mc [135]

Answer:

4cm

Explanation:

Hello!

To solve this problem use the following steps, the procedure is attached.

1. draw the complete outline of the problem

2. Use the continuation equation that states that the volumetric flow at the inlet of the pipe is the same as it should come out, remember that the flow is the product of the cross-sectional area by the flow rate, finally use algebra and input data to Find the exit diameter.

8 0
3 years ago
When a mass of 24 g is attached to a certain spring, it makes 21 complete vibrations in 3.3 s. What is the spring constant of th
lyudmila [28]

Answer: 3.889N/m

Explanation:

f=(1/2)*√k/m

f=n/t

f= 21/3.3=6.4Hz

6.4*2=√k/m

12.73=√k/m

12.73^2=k/m

162.0529=k/m

Since m=24g

Convert g to kg

m=24/1000

m=0.024kg

K=162.0529*0.024

K=3.889N/m

4 0
3 years ago
Name two elements that have similar properties. How can you tell using the periodic table?
tangare [24]
Helium and nitrogen because they are both from the noble gas group.
7 0
4 years ago
Which type of scanner uses X-rays, and why?
Mashutka [201]

Answer:

C.  Security baggage scanners, because X-rays either pass through or are absorbed by the objects in the baggage, creating an image of the objects

3 0
3 years ago
Read 2 more answers
Geronimo wants to move an object 12 meters. Calculate the net work done by the object with an applied force of 150 N and a frict
valina [46]

Answer:

1476 J

Explanation:

From the question,

Net Work done = Net force× distance moved by net force.

W' = (F-F')×d................... Equation 1

Where W' = Net work done, F = force applied, F' = Frictional force, d = distance moved.

Given: F = 150 N, F' = 37 N, d = 12 m

Substitute these values into equation 1

W' = (150-37)×12

W' = 123×12

W' = 1476 J.

hence the Net Work done by the object is 1476 J

4 0
3 years ago
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