8.66mls = v1
vf2 = vi2 + a(d)
(0mls) squared = visquared + - 5mls squared (15m)
0mls squared = vi2 - 75m squared / s squared
75 m squared/s squared = vi
Hope this helps!
The equation would be set in acceleration form, and after plugging in, it would read: a= 10 m/s-0m/s divided by 3 seconds. It equaling 3.3 bar notation and units measuring m/s squared. i’M pRobAbLy wRoNg
Answer:
W= 638.1 J
Explanation:
As we know that
Work done is the area of the force and displacement diagram.
W=∫F.dx
W=Work
F=force
dx=Elemental displacement
From the diagram ,area A
A= 60 x 7.09 + 1/2 x 60 x 7.09
A= 638.1 J
So the work W
W= 638.1 J
<span>vf^2 = vi^2 + 2*a*d
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vf = velocity final
vi = velocity initial
a = acceleration
d = distance
---
since the airplane is decelerating to zero, vf = 0
---
0 = 55*55 + 2*(-2.5)*d
d = (-55*55)/(2*(-2.5))
d = 605 meters
</span>
