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3 years ago

Where is the mass of an atom found? Explain.

Chemistry

1 answer:

muminat3 years ago

4 0

Explanation:

Over 99.9% percent of an atom's mass resides in the nucleus. The protons and neutrons in the center of the atom are about 2000 times heavier than the electrons orbiting around it.

Because the electrons are so light by comparison,they represent only a tiny fraction of a percent of the atom's total weight.

Hope this answer helps you!

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3 years ago

If an atom has 5 valence electrons, how many electrons does it need to gain to achieve a stable electron configuration?

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It needs to gain 3 valence electrons

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3 years ago

A 1.00 kg sample of Sb2S3 (s) and a 10.0 g sample of H2 (g) are allowed to react in a 25.0 L container at 713 K. At equilibrium,

Scorpion4ik [409]

Answer: The value of $K_c$ is coming out to be 0.412

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For $Sb_2S_3$

Given mass of $Sb_2S_3$ = 1.00 kg = 1000 g (Conversion factor: 1 kg = 1000 g)

Molar mass of $Sb_2S_3$ = 339.7 g/mol

Putting values in equation 1, we get:

$\text{Moles of }Sb_2S_3=\frac{1000g}{339.7g/mol}=2.944mol$

For hydrogen gas:

Given mass of hydrogen gas = 10.0 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen gas}=\frac{10.0g}{2g/mol}=5mol$

For hydrogen sulfide:

Given mass of hydrogen sulfide = 72.6 g

Molar mass of hydrogen sulfide = 34 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen sulfide}=\frac{72.6g}{34g/mol}=2.135mol$

The chemical equation for the reaction of antimony sulfide and hydrogen gas follows:

$Sb_2S_3(s)+3H_2(g)\rightarrow 2Sb(s)+3H_2S(g)$

Initial: 2.944 5

At eqllm: 2.944-x 5-3x 2x 3x

We are given:

Equilibrium moles of hydrogen sulfide = 2.135 moles

Calculating for 'x', we get:

$\Rightarrow 3x=2.135\\\\\Rightarrow x=\frac{2.135}{3}=0.712$

Equilibrium moles of hydrogen gas = (5 - 3x) = (5 - 3(0.712)) = 2.868 moles

Volume of the container = 25.0 L

Molarity of a solution is calculated by using the formula:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}$

The expression of $K_c$ for above equation, we get:

$K_c=\frac{[H_2S]^3}{[H_2]^3}$

The concentration of solids and liquids are not taken in the expression of equilibrium constant.

$K_c=\frac{(\frac{2.135}{25})^3}{(\frac{2.868}{25})^3}\\\\K_c=0.412$

Hence, the value of $K_c$ is coming out to be 0.412

3 0

3 years ago

In solution, strong acids and bases ionize completely, but weak acids and bases ionize only partially.

Vadim26 [7]

Answer:

The given statement is true.

Explanation:

Strong acids and bases act as strong electrolytes.They undergo complete dissociation in an aqueous medium to generate cations and anions.

For example HCl ⇄ H+ + Cl-

Hydrochloric acid is a strong electrolyte,it undergo complete dissociation in an aqueous solution to generate H+ ion and Cl- ion.

On the other hand acetic acid is a weak acid and act as weak electrolyte.In aqueous solution acetic acid under partial dissociation to form acetate anion and proton.

CH3COOH ⇄ CH3COO- + H+

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4 years ago

Which would be a common-sense practice in a lab environment??

lana66690 [7]

I think you forgot to give the options along with the question. I am answering the question based on my research and knowledge. Using safe research practices would be a very good common-sense practice in a lab environment. I hope that this is the answer that has actually come to your desired help.

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3 years ago