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maria [59]
3 years ago
7

Two gas samples have the same number of molecules, the same volume, and the same pressure. Which of the following could be true?

Chemistry
1 answer:
OverLord2011 [107]3 years ago
6 0
The choices are:
<span>A. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 0</span>°<span>C.
B. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 298 K.
C. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 273</span>°<span> C.
D. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 100</span>°<span> C.

The correct answer is A because the two gases will have the same temperature and 273 K = 0</span>°C
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Electrochemistry - Equilibrium
Ipatiy [6.2K]

Answer:

Explanation:

The relation between equilibrium constant and Ecell is given below .

E⁰cell = (RT / nF ) lnK  , F is faraday constant T is 273 + 25 = 298 K

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.25 = (8.314 x 298  lnK) / (2 x 96485 )

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n = 4

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= 474706 J / mol

3 )

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Mg(OH)2 is a sparingly soluble salt with a solubility product, Ksp, of 5.61×10−11. It is used to control the pH and provide nutr
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Answer:

The ration of the molar solubility is 165068.49.

Explanation:

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Mg(OH)_{2}\Leftrightarrow Mg^{2+}(aq)+2(OH)^{-}(aq)

              [Mg^{2+}][OH^{-}]

Initial      0          0

Equili     +S       +2S

Final      S          2S

K_{sp}=[Mg^{2+}][OH^{-}]

5.61\times 10^{-11}=(S)(2S)^{2}

S=(\frac{5.61\times 10^{-11}}{4})^{1/3}=2.41\times 10^{-4}M

Solubility of Mg(OH)_{2} in 0.180 M NaOH is a follows.

Mg(OH)_{2}\Leftrightarrow Mg^{2+}(aq)+2(OH)^{-}(aq)

              [Mg^{2+}][OH^{-}]

Initial      0          0

Equili     +S       +2S

Final      S          2S+0.180M

K_{sp}=[Mg^{2+}][OH^{-}]

5.61\times 10^{-11}=(S)(2S+0.180)^{2}

S=1.46\times 10^{-9}M

Ratio\,of\,solubility=\frac{2.41\times 10^{-4}}{1.46\times 10^{-9}}=165068.49

Therefore, The ration of the molar solubility is 165068.49.

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