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3 years ago

As you move from left to right across the periodic table elements ?

Chemistry

1 answer:

Sidana [21]3 years ago

6 0

Explanation:

Quite a number of properties varies across a period. Some remains constant whereas others decreases.

As one moves from left to right;

The energy level remains the same.
The ionization energy increases progressively as a result of increasing nuclear charge.
Electron affinity increases from left to right.
Electronegativity increases.
Electropositivity decreases.

learn more:

Periodic table brainly.com/question/2014634

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Is mercury a solution

Dvinal [7]

Answer:

No.

Explanation:

Mercury is not a solution. It is a detonator.

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3 years ago

I need someones help

valentinak56 [21]

Answer:

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2 years ago

Round each number to three significant figures. 0.036549:

valina [46]

Answer:

0.0365

Explanation:

Three significant figures after the decimal include all numbers except the zeros before other numbers.

For example 0.000003431232 to three significant figures would be 0.00000343. However if the numbers are before the decimal, the zeros are included, for example 19828300 to three significant numbers would be 19800000.

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3 years ago

What is the rate constant for the reaction 2a+b→c? (the initial rate was measured at several different reactant concentrations)

ozzi

To find the rate constant we can write a rate expression for the following reaction:

2A + B → C

A rate expression is written as some rate constant multiplied by the concentrations of the reactants, with each concentration raised to the power of the molar coefficient. [A] has a coefficient of 2, and [B] has a coefficient of 1. Therefore, we get the following rate expression:

rate = k[A]²[B]

We are given a table of values and we can enter the three variable to solve for k.

k = (rate)/([A]²[B])
k = (0.035)/((0.05)²(0.05))
k = 280

We can confirm if the value for k is correct by using another set of concentrations, along with the rate constant and solve for the rate.

rate = 280 [0.10]²[0.05]
rate = 280 (0.01)(0.05)
rate = 0.14

The value we solved for agrees with the rate provided in the table, therefore we know our value for the rate constant is correct which is k = 280.

6 0

3 years ago

A 0.100 M solution of chloroacetic acid 1ClCH2COOH2 is 11.0% ionized. Using this information, calculate 3ClCH2COO-4, 3H 4, 3ClCH

bearhunter [10]

Answer:

[CICH2COOH] = 0.089 M

[CICH2COO-] = 0.011 M

[H+] = 0.011 M

Ka = 1.36 x 10^-3

Explanation:

The reaction

CICH2COOH ⇄ H+ (aq) + CICH2COO- (aq)

The initial concentration of CICH2COOH is 0.10 M , chloroacetic acid is 11.0% ionized.

let us calculate Ka

First , find change in concentration

since , 11% ionized

change in concentration = 0.10 X 11% = 0.011 M

Initial Concentration of CICH2COOH = 0.10 M

change in concentration of CICH2COOH = - 0.011 M

Equilibrium Concentration of CICH2COOH = 0.10 M - 0.011 M = 0.089 m

Initial Concentration of CICH2COO- = 0 M

change in concentration of CICH2COO- = + 0.011 M

Equilibrium Concentration of CICH2COO- = 0.011 M

Initial Concentration of H+ = 0 M

change in concentration of H+ = + 0.011 M

Equilibrium Concentration of H+ = 0.011 M

Therefore,

[CICH2COOH] = 0.089 M

[CICH2COO-] = 0.011 M

[H+] = 0.011 M

Ka = [H+][CICH2COO-] /[CICH2COOH]

Ka = (0.011 * 0.011) / (0.089)

Ka = 1.36 x 10^-3

6 0

3 years ago