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Mariulka [41]
3 years ago
13

The heat released by burning candle is an example of thermal energy

Physics
2 answers:
trasher [3.6K]3 years ago
5 0
That is false because thermal energy is the heat inside the candle so the only one that would make sense is chemical bonds
yawa3891 [41]3 years ago
4 0
False the correct answer is chemical bonds instead of thermal energy
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What is the force on a body of mass 20 kg moving with an acceleration of 3 m/s2 ?
zubka84 [21]

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<em>Sol</em><em>ution</em><em>,</em>

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<em>Force</em><em>=</em><em>?</em>

<em>Now</em><em>,</em>

<em>Force</em><em>=</em><em>m</em><em>*</em><em>g</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>2</em><em>0</em><em>*</em><em>3</em>

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5 0
3 years ago
Read 2 more answers
An airplane flies at airspeed (relative to the air) of 280 km/h . The pilot wishes to fly due North (relative to the ground) but
MrRa [10]

Answer:

the pilot should head the plane 7.547^{\circ} towarrds south- west

Solution:

The airspeed of the airplane, v = 280 km/h

The velocity of the wind, v' = 52 km/h South-west

Angle, \theta = 225^{\circ}

Now, measured angle in the clockwise direction from North:

sin225 = sin(\pi + 45) =  - sin 45^{\circ}

Now,

vsinx - v'sin45 = 0

280sinx = 52sin45

x = sin^{- 1}(\frac{52}{280}\times \frac{1}{\sqrt{2}})

x = 7.547^{\circ} south- west

4 0
3 years ago
Question :
riadik2000 [5.3K]

The second law of motion states that: the acceleration of an object is dependent upon two variables: - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object

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Motion can be defined as the process of changing position willingly or due to a force applied.

Motion can be seen in different forms and types depending on the object.

In conclusion, The second law of motion is used to deduce the formula for acceleration.

Learn more about second law of motion: brainly.com/question/2009830

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8 0
2 years ago
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If your vehicle has a steering wheel lock, should you ever turn off the ignition while it is moving?
umka2103 [35]

It is not advisable to turn off the ignition while it is moving, so it is a no. Why? Even though the vehicle has steering wheel lock, turning off the ignition while it is moving is not advisable because it causes the vehicle to lose out of control, leading to complications and accidents.

5 0
3 years ago
Where is the near point of an eye for which a contact lens with a power of +2.55 diopters is prescribed?Where is the far point o
tankabanditka [31]

Answer:

(a). The eye's near point is 68.98 cm from the eye.

(b). The eye's far point is 33.33 cm from the eye.

Explanation:

Given that,

Power = 2.55 D

Object distance = 25 cm for near point

Object distance = ∞ for far point

Suppose where is the far point of an eye for which a contact lens with a power of -3.00 D  is prescribed for distant vision?

(a) We need to calculate the focal length

Using formula of power

f =\dfrac{1}{P}

Put the value into the formula

f=\dfrac{100}{2.55}

f=39.21\ cm

We need to calculate the image distance

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{39.21}=\dfrac{1}{v}-\dfrac{1}{-25}

\dfrac{1}{39.21}-\dfrac{1}{25}=\dfrac{1}{v}

\dfrac{1}{v}=-\dfrac{1421}{98025}

v=-68.98\ cm

The eye's near point is 68.98 cm from the eye.

(b). We need to calculate the focal length

Using formula of power

f =\dfrac{1}{P}

Put the value into the formula

f=-\dfrac{100}{3.00}

f=-33.33\ cm

We need to calculate the image distance

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{-33.33}=\dfrac{1}{v}-\dfrac{1}{\infty}

-\dfrac{1}{33.33}+\dfrac{1}{\infty}=\dfrac{1}{v}

\dfrac{1}{v}=-\dfrac{1}{33.33}

v=-33.33\ cm

The eye's far point is 33.33 cm from the eye.

Hence, (a). The eye's near point is 68.98 cm from the eye.

(b). The eye's far point is 33.33 cm from the eye.

5 0
3 years ago
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