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AlexFokin [52]
3 years ago
13

Is it possible to produce a continuous and oriented aramid fiber–epoxy matrix composite having longitudinalandtransverse moduli

of elasticity of 35 GPa (5×106psi) and 5.17 GPa (7.5×105psi), respectively? Why or why not?Assume that the elastic modulus of the epoxy is 3.4 GPa (4.93×105psi).Also, the value ofEfor aramid fibers is 131GPa.
Physics
1 answer:
Masja [62]3 years ago
5 0

Answer:

Not possible

Explanation:

E_{cl} = longitudinal modulus of elasticity = 35 Gpa

E_{ct} = transverse modulus of elasticity = 5.17 Gpa

E_m = Epoxy modulus of elasticity = 3.4 Gpa

V_{\rho l} = Volume fraction of fibre (longitudinal)

V_{\rho t} = Volume fraction of fibre (transvers)

E_f = Modulus of elasticity of aramid fibers = 131 Gpa

Longitudinal modulus of elasticity is given by

E_{cl}=E_m(1-V_{\rho l})+E_fV_{\rho l}\\\Rightarrow 35=3.4(1-V_{\rho l})+131V_{\rho l}\\\Rightarrow 35=3.4-3.4V_{\rho l}+131V_{\rho l}\\\Rightarrow V_{\rho l}=\frac{35-3.4}{131-3.4}\\\Rightarrow V_{\rho l}=0.24764

Transverse modulus of elasticity is given by

E_{ct}=\frac{E_mE_f}{(1-V_{\rho t})E_f+V_{\rho t}E_m}\\\Rightarrow 5.17=\frac{3.4\times 131}{(1-V_{\rho t})131+V_{\rho t}3.4}\\\Rightarrow \frac{3.4\times 131}{5.17}-131=-127.6V_{\rho t}\\\Rightarrow V_{\rho t}=\frac{\frac{3.4\times 131}{5.17}-131}{-127.6}\\\Rightarrow V_{\rho t}=0.35148

V_{\rho l}\neq V_{\rho t}

Hence, it is not possible to produce a continuous and oriented aramid fiber.

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Answer:

Double blind experiment

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The experiment give rise to very accurate results , which is very important for any experiment .

Hence , the new director Margaret , need to design a set of double - blind experiments.

7 0
4 years ago
At constant pressure, a sample of a gas occupies 420 ml at 220 K. what volume does the gas occupy at 250 K?
soldier1979 [14.2K]

Answer:

480 mL

Explanation:

Ideal gas law states:

PV = nRT

At constant pressure, nR/P is constant.  Therefore:

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3 years ago
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Anni [7]
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8 0
3 years ago
As a 2.0-kg object moves from (4.4 i + 5j) m to ( 11.6 i - 2j) m, the constant resultant force
aliina [53]

Answer:

v_f = 10.38 m / s

Explanation:

For this exercise we can use the relationship between work and kinetic energy

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note that the two quantities are scalars

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          W = F. Δx

the bold are vectors.  The displacement is

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          W = (4 i - 9j). (7.2 i - 7 j)

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we substitute in the initial equation

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          v_f² = 2/2 (91.8 + 16)

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          v_f = 10.38 m / s

3 0
3 years ago
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t=\frac{S}{v}=\frac{150 km}{50 km/h}=3 h

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3 0
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